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leonid [27]
3 years ago
10

A child throws a ball perfectly horizontally at the same time a dirt clod falls off it atthe same height above the ground. The c

lod falls vertically downward. Ignoring airresistance, the time when the clod hits the ground will
A) be equal to the time the ball hits the ground
B) be earlier than when the ball hits
C) be later than when the ball hits
D) not depend upon how high it started falling from
Physics
1 answer:
Oksana_A [137]3 years ago
6 0

Answer: A.). Be equal to the time the ball hits the group

Explanation:

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A. a material burns out when current is excessive

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Who needs to know physics when they are making a satellite
vladimir2022 [97]
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4 0
4 years ago
Im stuck on number 4, am I just supposed to talk about theory because there is no given info.
Strike441 [17]

Explanation:

Assuming no air resistance, the horizontal acceleration at all points is 0, and the vertical acceleration at all points is -g (if near the surface of the Earth, -9.8 m/s²).

6 0
4 years ago
Add a vector whose magnitude is 13 with angle 27 degrees to one whose magnitude is 11 with angle 45 degrees? Put the length firs
mafiozo [28]

Answer:

Magnitude of the vector is 23.75\ \text{units} and the direction is 35.23^{\circ}

Explanation:

Magnitude of first vector = |A| = 13\ \text{units}

Angle = \theta_1=27^{\circ}

Magnitude of second vector = |B| = 11\ \text{units}

Angle = \theta_2=45^{\circ}

x component of first vector

A_{x}=|A|\cos\theta_1\\\Rightarrow A_x=13\cos27^{\circ}\\\Rightarrow A_x=11.6\ \text{units}

y component of first vector

A_{y}=|A|\sin\theta_1\\\Rightarrow A_y=13\sin27^{\circ}\\\Rightarrow A_y=5.9\ \text{units}

x component of second vector

B_{x}=|B|\cos\theta_2\\\Rightarrow B_x=11\cos45^{\circ}\\\Rightarrow B_x=7.8\ \text{units}

y component of first vector

B_{y}=|B|\sin\theta_2\\\Rightarrow B_y=11\sin45^{\circ}\\\Rightarrow A_y=7.8\ \text{units}

Adding the magnitudes

C_x=A_x+B_x=11.6+7.8\\\Rightarrow C_x=19.4\ \text{units}

C_y=A_y+B_y=5.9+7.8\\\Rightarrow C_y=13.7\ \text{units}

Magnitude of the sum of the vectors would be

|C|=\sqrt{C_x^2+C_y^2}\\\Rightarrow |C|=\sqrt{19.4^2+13.7^2}=23.75\ \text{units}

The direction would be

\theta=\tan^{-1}\dfrac{C_y}{C_x}\\\Rightarrow \theta=\tan^{-1}\dfrac{13.7}{19.4}\\\Rightarrow \theta=35.23^{\circ}

The magnitude of the vector is 23.75\ \text{units} and the direction is 35.23^{\circ}

4 0
3 years ago
An electron has a mass of 9.1x10-31 kg. What is
zloy xaker [14]

Answer:

3.185×10^-29 kgm/s

Explanation:

Momentum(p)=mass×velocity

=9.1×10^-31×3.5×10

=3.185×10^-29 kgm/s

4 0
3 years ago
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