1. Octagon 8 sides
2. Hexagon 6 sides
3. Pentagon 5 side
4. Rectangle 4 side
5. Square 4 sides
6. Triangle 3 side
I don’t know if that’s what u meant
Answer:
Kb = 1.6 × 10⁻⁵
Explanation:
Step 1: Given data
Acid dissociation constant of hydrocyanic acid (Ka): 6.2 × 10⁻¹⁰
Concentration of cyanide ion (Cb): 0.1 M
Step 2: Calculate the basic dissociation constant (Kb) of cyanide ion
We have the Ka of HCN. We can calculate the Kb of its conjugate base using the following expression.
Ka × Kb = Kw = 1.0 × 10⁻¹⁴
Kb = 1.0 × 10⁻¹⁴/Ka
Kb = 1.0 × 10⁻¹⁴/6.2 × 10⁻¹⁰
Kb = 1.6 × 10⁻⁵
Answer:
The process of slowly adding one solution to another until the reaction between the two is complete.
Explanation:
When you perform a titration, you are slowly adding one solution of a known concentration called a titrant to a known volume of another solution of an unknown concentration until the reaction reaches neutralization, in which the reaction is no longer taking place. This is often indicated by a color change.
Hope that helps.
Answer:
The reason is because matter is anytine that occupies space and possesses mass
Answer:
0.44 L.
Explanation:
Density of nickel(II) chloride = 29.8 g/dL.
Mass of nickel(II) chloride = 131 g
Volume of nickel(II) chloride =?
Next, we shall convert 29.8 g/dL to g/L. This can be obtained as follow:
Recall:
1 g/dL = 10 g/L
Therefore,
29.8 g/dL = 29.8 x 10 = 298 g/L
Therefore, 29.8 g/dL is equivalent to 298 g/L.
Finally, we shall determine the volume of nickel(II) chloride as follow:
Density of nickel(II) chloride = 298 g/L
Mass of nickel(II) chloride = 131 g
Volume of nickel(II) chloride =?
Density = mass /volume
298 = 131/Volume
Cross multiply
298 x Volume = 131
Divide both side by 298
Volume = 131/298
Volume = 0.44 L
Therefore, the volume of of nickel(II) chloride is 0.44 L