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melomori [17]
3 years ago
6

What mass of sucrose needs to be dissolved in 540 g of water in order to prepare a 15% by mass solution.

Chemistry
1 answer:
Lilit [14]3 years ago
5 0

Answer:

95.3g

Explanation:

Given parameters:

Mass of water  = 540g

Percentage by mass of solution = 15%

Unknown:

Mass of sucrose = ?

Solution;

To solve this problem, we must understand that a solution is made up of solute dissolved in a solvent. A solute is the solid dissolved in another. The solvent is the is dissolving medium;

    Percentage by mass of solute in solution = \frac{Mass of solute}{Mass of solution}  x 100

Mass of solution  = mass of water + Mass of sucrose  = 540 + M

  where M is the mass of sucrose;

therefore;

                 \frac{M}{540 + M }  x 100   = 15

   Solving for M gives 95.3g

Mass of sucrose is 95.3g

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statuscvo [17]
The answer is flourine

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4 0
3 years ago
Which is the limiting reagent in the following reaction given that you start with 15.5 g of Na2S and 12.1 g CuSO4? Reaction: Na2
NemiM [27]

Answer:

CuSO4

Explanation:

Na2S + CuSO4 → Na2SO4 + CuS

The reaction is balanced (same number of elements in each side)

To determine limiting reagent you need to know the moles you have of each.

Molar mass Na2S = 23 * 2 + 32 = 78

Molar mass CuSO4 = 63.5 + 32 + 16 * 4 = 159.5

Na2S mole = 15.5 / 78 = 0.2

CuSO4 mole = 12.1/159.5 = 0.076

*Remember mole = mass / MM

With that information now you have to divide each moles by its respective stoichiometric coefficient

Na2S stoichiometric coefficient : 1

Na2S : 0.2 / 1 = 0.2

CuSO4 stoichiometric coefficient: 1

CuSO4: 0.076 / 1 = 0.076

The smaller number between them its the limiting reagent, CuSO4

8 0
3 years ago
Please help! Which Zeros are significant in the measurement .0506010 kg?
Vitek1552 [10]
It would be a,b,c as the answer. hope this helps!
7 0
3 years ago
Methylene chloride (CH2Cl2) has fewer chlorine atoms than chloroform (CHCl3). Nevertheless, methylene chloride has a larger mole
icang [17]

Answer:

Explanation has been given below.

Explanation:

  • Chloroform has three polar C-Cl bonds. Methylene chloride has two polar C-Cl bonds. So it is expected that chloroform should be more polar and posses higher dipole moment than methylene chloride.
  • Two factors are liable for the opposite trend observed in dipole moments of methylene chloride and chloroform.
  • First one is the number of hyperconjugative hydrogen atoms present in a molecule. Hyperconjugation occurs with vacant d-orbital of Cl atom. Hyperconjugation amplifies charge separation in a molecule resulting higher dipole moment.
  • Methylene chloride has two hyperconjugative hydrogen atoms and chloroform has one hyperconjugative hydrogen atom.Therefore methylene chloride should have higher charge separation as compared to chloroform.
  • Second one is induction of opposite polarity in a C-Cl bond by another C-Cl bond in a molecule. Higher the opposite induction of polarity, lower the charge separation in a molecule and hence lower the dipole moment of a molecule.
  • Chloroform has three C-Cl bonds and methylene chloride has two C-Cl bonds. Therefore opposite induction is higher for chloroform resulting it's lower dipole moment.
3 0
4 years ago
How many moles of molecules are in 40g of H2O?
soldier1979 [14.2K]
Molecular mass of H2O is: 16+2*1=18
so moles of 40g of H2O is: 40/18=2.22
6 0
3 years ago
Read 2 more answers
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