Question

What mass of sucrose needs to be dissolved in 540 g of water in order to prepare a 15% by mass solution.

Answer 1

Answer:

95.3g

Explanation:

Given parameters:

Mass of water  = 540g

Percentage by mass of solution = 15%

Unknown:

Mass of sucrose = ?

Solution;

To solve this problem, we must understand that a solution is made up of solute dissolved in a solvent. A solute is the solid dissolved in another. The solvent is the is dissolving medium;

    Percentage by mass of solute in solution = $\frac{Mass of solute}{Mass of solution} x 100$

Mass of solution  = mass of water + Mass of sucrose  = 540 + M

  where M is the mass of sucrose;

therefore;

                 $\frac{M}{540 + M } x 100$   = 15

   Solving for M gives 95.3g

Mass of sucrose is 95.3g