One kilogram is equal to one thousand grams. Further, one gram is equal to 1000 mg. The conversion is as shown below,
(6.285 x 10³ mg) x (1 g / 1000 mg) x (1 kg / 1000 g)
The numerical value of the operation above is 0.006285 kg.
Answer:
This is simple, if it has a high flammability, and you light it on fire, then that would be a chemical change.
Explanation:
May I have brainliest please? :)
In an ideal gas, there are no attractive forces between the gas molecules, and there is no rotation or vibration within the molecules. The kinetic energy of the translational motion of an ideal gas depends on its temperature. The formula for the kinetic energy of a gas defines the average kinetic energy per molecule. The kinetic energy is measured in Joules (J), and the temperature is measured in Kelvin (K).
K = average kinetic energy per molecule of gas (J)
kB = Boltzmann's constant ()
T = temperature (k)
Kinetic Energy of Gas Formula Questions:
1) Standard Temperature is defined to be . What is the average translational kinetic energy of a single molecule of an ideal gas at Standard Temperature?
Answer: The average translational kinetic energy of a molecule of an ideal gas can be found using the formula:
The average translational kinetic energy of a single molecule of an ideal gas is (Joules).
2) One mole (mol) of any substance consists of molecules (Avogadro's number). What is the translational kinetic energy of of an ideal gas at ?
Answer: The translational kinetic energy of of an ideal gas can be found by multiplying the formula for the average translational kinetic energy by the number of molecules in the sample. The number of molecules is times Avogadro's number:
Answer:
the answer is 1:3:2
Hope this helps, let me know if you need any other help, Stoichiometry is hard
