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konstantin123 [22]
2 years ago
10

Does the orbital period of a planet depend on the mass of the planet or on the mass of the star that it orbits?

Physics
1 answer:
jasenka [17]2 years ago
8 0

Answer:

The orbital period of a planet depends on the mass of the planet.

Explanation:

A less massive planet will take longer to complete one period than a more massive planet.

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What kind of research in teaching of physical science can be done???​
11Alexandr11 [23.1K]

Answer:

Physical sciences are those academic disciplines that aim to uncover the underlying laws of nature - often written in the language of mathematics. It is a collective term for areas of study including astronomy, chemistry, materials science and physics.

Explanation:

3 0
3 years ago
Car A starts out traveling at 35.0 km/h and accelerates at 25.0 km/h2 for 15.0 min. Car B starts out traveling at 45.0 km/h and
lawyer [7]

1 kilometre=1000 metre

      1 hour = 3600 second

       1\ km/hr=\frac{1000}{3600} m/s

       1\ km/hr=\frac{5}{18} m/s

The initial velocity of car A is 35.0 km/hr i.e

                                         35.0\ km/hr=35*\frac{5}{18} m/s

                                                                   = 9.72 m/s

The initial velocity of car B is 45 km/hr =12.5 m/s

The initial velocity of car C is 32 km/hr = 8.89 m/s

The initial velocity of car D is 110 km/hr=30.56 m/s

The acceleration of car A is given as  25\ km/hr^2

                                            =\ 25*\frac{1000}{3600*3600} m/s^2

                                            =0.00192901234 m/s^2

The time taken by car A = 15 min.

From equation of kinematics we know that-

                                 v= u+at      [Here v is the final velocity and a is the acceleration and t is the time]

Final velocity of A,  v = 9.72 m/s +[0.00192901234×15×60]m/s

                                   =11.456111106 m/s

The acceleration of B is given as    15\ km/hr^2

                                    =0.00115740740740 m/s^2

The time taken by car B =20 min

The final velocity of B is -

                             v= u+at

                               = u-at    [Here a is negative due to deceleration]

                               =12.5 m/s +[0.0011574074074×20×60]

                               =13.8888888.....

                               =13.9

The acceleration of C is given as    40\ km/hr^2          

                                                            =\ 0.003086419753 m/s^2

The time taken by car C =30 min

The final velocity of C is-

                                v = u+at

                                   =8.89 m/s+[0.003086419753×30×60] m/s

                                   =14.4455555555..m/s

                                   =14.45 m/s

The car C is decelerating.The deceleration is given as-  60\ km/hr^2

                                                                      =0.0046296296296m/s^2

The time taken by car D= 45 min.

The final velocity of the car D is-

                     v =u+at

                        =30.56 -[0.00462962962962×45×60]m/s

                        =18.06 m/s

Hence from above we see that the magnitude of final velocity car C and B is close to 15 m/s. The car C is very close as compared to car B.

                 


3 0
3 years ago
Match the boundary with its characteristic
kondor19780726 [428]
<span>Matching the boundary with its characteristics 1. Convergent - C. Compression 2. Divergent - B. Along ocean ridges 3. Transform - A. Along strike-slip faults The compression that occur in the convergent boundary causes the reverse fault in the earth crust. So in the divergent boundary two crust plates move apart causing a normal fault along the ocean ridges. The faults in the transform boundary happens at the place where plates slide laterally.</span>
7 0
3 years ago
Read 2 more answers
How far does a car travel as it accelerates from 12 m/s to 18 m/s at 3 m/s??
yulyashka [42]

Answer:

Explanation:

I ASSUME you mean acceleration is 3 m/s²

v² = u² + 2as

s = (v² - u²) / 2a

s = (18² - 12²) / (2(3))

s = 30 m

to verify we can see that the acceleration time is

t = (18 - 12) / 3 = 2 s

s = 0 + 12(2) + ½(3)2² = 30 m

4 0
2 years ago
A capacitor consists of a set of two parallel plates of area A separated by a distance d . This capacitor is connected to a batt
Elis [28]

Answer:

if we double the distance the energy stored will be doubled also

Explanation:

The energy stored in a capacitor is given as

Energy stored =1/2(cv²)

Or

= 1/2(Qv)

Where c = capacitance

Q= charge

But the electric field is expressed as

E= v/d

where v= voltage

d= distance

v=Ed

Substituting into any equation above say

Energy stored =1/2(Qv)

Substituting v=Ev

Energy stored =1/2(QEd)

From the equation above it shows that if we double the distance The energy stored will be doubled also

5 0
3 years ago
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