The solution for this problem is:
If they feel 50% of their weight that means that the
centripetal force is also 50% of their weight 1g - 0.5g = 0.5g
Then 0.5* 9.8m/s² * 18m = 88.2 would be v²
Then get the square root, the answer would be:
and v = 9.391 m/s is the answer.
Answer:
AM radio = 540 - 1650 KHz
FM radio = 88 to 108 MHz
Television = 54 to 216 MHz
Weight = (mass) x (gravity)
70 N = (mass) x (9.8 m/s²)
Divide each side by (9.8 m/s²) , and you have
mass = 70 N / 9.8 m/s² = 7.14 kg.
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Mass on the moon:
Mass doesn't change. It's a number that belongs to the bowling ball,
no matter where the ball goes. If the mass of the bowling ball is 7.14 kg
anywhere, then it's 7.14 kg everywhere ... on Earth, on the moon, on Mars, rolling around in the trunk of my car, or floating in intergalactic space.
However, WEIGHT depends on the gravity wherever the ball happens to be
at the moment.
The acceleration of gravity on the moon is 1.622 m/s².
So the WEIGHT of the ball on the moon is
(7.14 kg) x (1.622 m/s²) = 11.58 Newtons
That's only about 16% of its weight on Earth.
