Answer:
r = 4.24x10⁴ km.
Explanation:
To find the radius of such an orbit we need to use Kepler's third law:
<em>where T₁: is the orbital period of the geosynchronous Earth satellite = 1 d, T₂: is the orbital period of the moon = 0.07481 y, r₁: is the radius of such an orbit and r₂: is the orbital radius of the moon = 3.84x10⁵ km. </em>
From equation (1), r₁ is:
![r_{1} = r_{2} \sqrt[3] {(\frac{T_{1}}{T_{2}})^{2}}](https://tex.z-dn.net/?f=%20r_%7B1%7D%20%3D%20r_%7B2%7D%20%5Csqrt%5B3%5D%20%7B%28%5Cfrac%7BT_%7B1%7D%7D%7BT_%7B2%7D%7D%29%5E%7B2%7D%7D%20)
![r_{1} = 3.84\cdot 10^{5} km \sqrt[3] {(\frac{1 d}{0.07481 y \cdot \frac{365 d}{1 y}})^{2}}](https://tex.z-dn.net/?f=%20r_%7B1%7D%20%3D%203.84%5Ccdot%2010%5E%7B5%7D%20km%20%5Csqrt%5B3%5D%20%7B%28%5Cfrac%7B1%20d%7D%7B0.07481%20y%20%5Ccdot%20%5Cfrac%7B365%20d%7D%7B1%20y%7D%7D%29%5E%7B2%7D%7D%20)
Therefore, the radius of such an orbit is 4.24x10⁴ km.
I hope it helps you!
Find the angles which the vecotr <span><span><span><span><span>v </span><span>⃗ </span></span>=3i−6j+2k</span> </span><span><span>v→</span>=3i−6j+2k</span></span>
makes with the coordinate axes.
If the angles are <span><span><span>α,β,θ</span> </span><span>α,β,θ</span></span>
, show that for any 3-dimensional vector:
. . . <span><span><span><span><span>cos </span><span>2 </span></span>α+co<span><span>s </span><span>2 </span></span>β+<span><span>cos </span><span>2 </span></span>θ=1</span> </span><span><span>cos2</span>α+co<span>s2</span>β+<span>cos2</span>θ=1</span></span>
Give me some answer choices and i will be happy to help
Answer:
D. Banks and offices closing on sunday.
Explanation:
Church is usually on sunday and people need a day off to do it because service is about 3 hours long. When banks and offices close on this day it shows how religion has affected our lives and our culture.
