a. 7.0 m/s
First of all, we need to convert the angular speed (1200 rpm) from rpm to rad/s:
Now we know that the row is located 5.6 cm from the centre of the disc:
r = 5.6 cm = 0.056 m
So we can find the tangential speed of the row as the product between the angular speed and the distance of the row from the centre of the circle:
b. 
The acceleration of the row of data (centripetal acceleration) is given by
where we have
v = 7.0 m/s is the tangential speed
r = 0.056 m is the distance of the row from the centre of the trajectory
Substituting numbers into the formula, we find
Answer:
The acceleration of the bag of sand is 
.
Explanation:
We have,
Mass of a bag of sand is 100 kg
Weight of the bag of sand is 100 N
It is required to find the acceleration of the bag when it is dropped. The weight of an object is given by :
When it is dropped, a = g
So, the acceleration of the bag of sand is .
What's your question? is it seprete questions
Answer:
The acceleration due to gravity at Pluto is 0.0597 m/s^2.
Explanation:
Length, L = 1 m
10 oscillations in 257 seconds
Time period, T = 257/10 = 25.7 s
Let the acceleration due to gravity is g.
Use the formula of time period of simple pendulum
