Question

PLS HELP THIS IS WORTH A LOT OF POINTS ON MY TEST. WILL GIVE BRAINLIEST

Answer 1

• Initial velocity=0m/s
• Acceleration=g=10m/s^2
• Time=t=6s

• Height be h

$\\ \rm\Rrightarrow h=\dfrac{1}{2}gt^2$

$\\ \rm\Rrightarrow h=\dfrac{1}{2}(10)(6)^2$

$\\ \rm\Rrightarrow h=5(36)$

$\\ \rm\Rrightarrow h=180m$

Answer 2

Answer:

Explanation:

By conservation of energy, speed of the ball going up = speed of ball coming down with the ball stops at the top.

Because the gravity acceleration is constant, by symmetry, half of total time, 6/2 = 3s, is for going up and the last 3s for coming down.

Consider the last 3s when the ball drops from top to bottom, the initial velocity = 0 and acceleration = 10m/s^2

distance traveled = initial velocity * time + 1/2 * acceleration * time^2

= 0*3 + 1/2*10*3^2

= 5*9

= 45m

So maximum height of the ball is 45m.