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fomenos
3 years ago
10

Is a 68.75 and a 70 a pass in 5th grade?

Engineering
2 answers:
ASHA 777 [7]3 years ago
6 0

Answer:

68.75 is not a passing grade for any grade you are in

and a 70 is barely a passing grade in any  grade

AleksAgata [21]3 years ago
6 0
You pass from 65 and above
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Water flows at low speed through a circular tube with inside diameter of 2 in. A smoothly contoured body of 1.5 in. diameter is
Art [367]

Answer:

Pressure = 11.38 psi

Force = 13.981 Ibf

Explanation:

Step by step solution is in the attached document.

5 0
3 years ago
Where loads are likely to be on continuously, the calculated load for branch circuits and feeders must be figured at (100%) (125
Anna [14]

Where loads are likely to be on continuously, the calculated load for branch circuits and feeders must be figured at 125%.

Section 210.19(A)(1) permits the bigger of the two values listed below to be utilized as the connectors 's ultimate size for sizing an ungrounded branch circuit conductor:

Without any extra adjustments or corrections, either 125% of the continuous load, OR

When adjustment and corrective factors are applied, the load is 100% (not 125% as stated previously).

This will be the same in the 2020 NEC. The introduction of new exception 2 is what has changed. To comprehend this new exception, one must study it very carefully. A part of a branch circuit connected to pressure connectors (such as power distribution blocks) that complies with 110.14(C)(2) may now be sized using the continuous load plus the noncontiguous load instead of 125% of the continuous load thanks to the new exception.

To know more about connectors click here:

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4 0
1 year ago
When brazing, the lowest effective brazing temperatures possible should be used to minimize the effects of heat on the base meta
nordsb [41]

Answer:

False

Explanation:

5 0
2 years ago
The hot combustion gases of a furnace are separated from the ambient air and its surroundings, which are at 25 oC, by a brick wa
yanalaym [24]

Answer:

T1 = 625.54 K

Explanation:

We are given;

T_α = Tsur = 25°C = 298K

h = 20 W/m².K,

L = 0.15 m

K = 1.2 W/m.K

ε = 0.8

Ts = T2 = 100°C = 373K

T1 = ?

Assumption:

-Steady- state condition

-One- dimensional conduction

-No uniform heat generation

-Constant properties

From Energy balance equation;

E°in - E°out = 0

Thus,

q"cond – q"conv – q"rad = 0

K[(T1 - T2)/L] - h(Ts-T_α) - εσ (Ts⁴ – Tsur⁴)

Where σ is Stephan-Boltzmann constant and has a value of 5.67 x 10^(-8)

Thus;

K[(T1 - T2)/L] - h(Ts-T_α) - εσ (Ts⁴ – Tsur⁴) = 1.2[(T1 - 373)/0.15] - 20(373 - 298] - 0.8x5.67x10^(-8)[373⁴ - 298⁴] = 0

This gives;

(8T1 - 2984) - (1500) - 520.31 = 0

8T1 = 2984 + 1500 + 520.31

8T1 = 5004.31

T1 = 5004.31/8

T1 = 625.54 K

7 0
3 years ago
What is the function of the following: 1- Oil rings 2- Flywheel 3- Timing gears
Tanya [424]

Answer:

Explanation:

The functions of the following are as follows:

1). Oil Rings:

  • Regulates oil within cylinder walls.
  • Helps to keep cylinder walls lubricated
  • Prevent Heat transfer
  • Reduce friction between piston and cylinder

2). Fly Wheel:

  • It is used to store rotational energy
  • It resist any change in rotational speed due to its moment of inertia
  • It helps to control the orientation of the mechanical system

3). Timing gears:

  • It provides synchronization in the rotation of crankshaft and the camshaft so as to provide proper valve opening and closing time during each cylinder's stroke(intake and exhaust).
4 0
3 years ago
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