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fomenos
3 years ago
10

Is a 68.75 and a 70 a pass in 5th grade?

Engineering
2 answers:
ASHA 777 [7]3 years ago
6 0

Answer:

68.75 is not a passing grade for any grade you are in

and a 70 is barely a passing grade in any  grade

AleksAgata [21]3 years ago
6 0
You pass from 65 and above
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In this exercise, you will write a Point structure that represents a space in two-dimensional space. This Point should have both
Afina-wow [57]

Answer:

Check the explanation

Explanation:

Points to consider:

We need to take the input from the user

We need to find the manhatan distance and euclidian using the formula

(x1, y1) and (x2, y2) are the two points

Manhattan:

|x_1 - x_2| + |y_1 - y_2|

Euclidian Distance:

\sqrt{(x1 - yl)^2 + (x2 - y2)^2)}

Code

#include<stdio.h>

#include<math.h>

struct Point{

  int x, y;

};

int manhattan(Point A, Point B){

  return abs(A.x - B.x) + abs(A.y- B.y);

}

float euclidean(Point A, Point B){

  return sqrt(pow(A.x - B.x, 2) + pow(A.y - B.y, 2));

}

int main(){

  struct Point A, B;

  printf("Enter x and Y for first point: ");

  int x, y;

  scanf("%d%d", &x, &y);

  A.x = x;

  A.y = y;

  printf("Enter x and Y for second point: ");

  scanf("%d%d", &x, &y);

  B.x = x;

  B.y = y;

  printf("Manhattan Distance: %d\n", manhattan(A, B));

  printf("Euclidian Distance: %f\n", euclidean(A, B));

 

}

Sample output

8 0
3 years ago
What should be given to a customer before doing a repair?
natima [27]
A. I believe, lmk if I’m right
7 0
3 years ago
A well insulated turbine operates at steady state. Steam enters the turbine at 4 MPa with a specific enthalpy of 3015.4 kJ/kg an
Anarel [89]

Answer:

power developed by the turbine = 6927.415 kW

Explanation:

given data

pressure = 4 MPa

specific enthalpy h1 = 3015.4 kJ/kg

velocity v1 = 10 m/s

pressure = 0.07 MPa

specific enthalpy h2 = 2431.7 kJ/kg

velocity v2 = 90 m/s

mass flow rate = 11.95 kg/s

solution

we apply here  thermodynamic equation that

energy equation that is

h1 + \frac{v1}{2}  + q = h2 + \frac{v2}{2}  + w

put here value with

turbine is insulated so q = 0

so here

3015.4 *1000 + \frac{10^2}{2}  =  2431.7 * 1000 + \frac{90^2}{2}  + w

solve we get

w = 579700 J/kg = 579.7 kJ/kg

and

W = mass flow rate × w

W = 11.95 × 579.7

W = 6927.415 kW

power developed by the turbine = 6927.415 kW

7 0
3 years ago
Question 21(Multiple Choice
Katen [24]

Answer:

four seconds

Explanation:

lookin at a vehicle respectively at a second can cause accident

8 0
3 years ago
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Water enters a boiler at a temperature of 110°F. The boiler is to produce 2000 lb/hr of steam at a pressure of 130 psia. How man
strojnjashka [21]
Yes it does the answer is no
5 0
2 years ago
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