3 years ago

Is a 68.75 and a 70 a pass in 5th grade?

Engineering

2 answers:

ASHA 777 [7]3 years ago

6 0

Answer:

68.75 is not a passing grade for any grade you are in

and a 70 is barely a passing grade in any grade

AleksAgata [21]3 years ago

6 0

You pass from 65 and above

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bixtya [17]

Answer:

h = 287.1 m

Explanation:

the density of mercury \rho =13570 kg/m3

the atmospheric pressure at the top of the building is

$p_t = \rho gh = 13570*908*0.73 = 97.08 kPa$

the atmospheric pressure at bottom

$p_b = \rho gh = 13570*908*0.75 = 100.4 kPa$

$\frac{w_{air}}{A} =p_b -p_t$

we have also

$(\rho gh)_{air} = p_b - p_t$

1.18*9.81*h = (100.4 -97.08)*10^3

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3 years ago

The link acts as part of the elevator control for a small airplane. If the attached aluminum tube has an inner diameter of 25 mm

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Answer:

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T = 600 * 0.15 = 90N.m

$T_max =\frac{T_c}{j} = \frac{x}{y} = \frac{90 \times 0.0175}{\frac{\pi}{2} \times (0.0175^4-0.0125^4)}$

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$T_{min} =\frac{T_c}{j} = \frac{x}{y} = \frac{90 \times 0.0125}{\frac{\pi}{2} \times (0.0175^4-0.0125^4)}$

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3 years ago

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Answer:

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Explanation:

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The function below takes two numeric parameters. The first parameter specifies the number of hours a person worked and the secon

Mekhanik [1.2K]

def calculate_pay(total_worked_hours, rate_per_hour):

if total_hours_worked > 40:

# anything over 40 hours earns the overtime rate

overtimeRate = 2 * rate _per_hour

return (40 * rate_per_hour) + ((total_worked_hours - 40) * overtimeRate

else:

# if you didn't work over 40 hours, there is no overtime

overtime = 0

return total_worked_hours * rate_per_hour

Explanation:

First we create the calculate_pay function which will takes 2 parameters.

Secondly ,inside the function we check if the total_worked_hours is greater than 40 and then return the pay by calculating with the help of formula for work over 40 hours.
If the total work hour is less than 40 then we return the pay by multiplying the total_worked_hours with rate_per_hour.

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3 years ago