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LiRa [457]
2 years ago
10

Water enters a boiler at a temperature of 110°F. The boiler is to produce 2000 lb/hr of steam at a pressure of 130 psia. How man

y BTU/hr are required? rantanmilar steel tanlic 14 feet long and 8 feet wide. It is filled to a height of 6' with oil which​
Engineering
1 answer:
strojnjashka [21]2 years ago
5 0
Yes it does the answer is no
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HELP PLEASE!!!!!!!!!!!
MAXImum [283]
C is your answers!!!!!$3&2)//
7 0
3 years ago
Read 2 more answers
The gas expanding in the combustion space of a reciprocating engine has an initial pressure of 5 MPa and an initial temperature
Anit [1.1K]

Answer:

a). Work transfer = 527.2 kJ

b). Heat Transfer = 197.7 kJ

Explanation:

Given:

P_{1} = 5 Mpa

T_{1} = 1623°C

                       = 1896 K

V_{1} = 0.05 m^{3}

Also given \frac{V_{2}}{V_{1}} = 20

Therefore, V_{2} = 1  m^{3}

R = 0.27 kJ / kg-K

C_{V} = 0.8 kJ / kg-K

Also given : P_{1}V_{1}^{1.25}=C

   Therefore, P_{1}V_{1}^{1.25} = P_{2}V_{2}^{1.25}

                     5\times 0.05^{1.25}=P_{2}\times 1^{1.25}

                     P_{2} = 0.1182 MPa

a). Work transfer, δW = \frac{P_{1}V_{1}-P_{2}V_{2}}{n-1}

                                  \left [\frac{5\times 0.05-0.1182\times 1}{1.25-1}  \right ]\times 10^{6}

                              = 527200 J

                             = 527.200 kJ

b). From 1st law of thermodynamics,

Heat transfer, δQ = ΔU+δW

   = \frac{mR(T_{2}-T_{1})}{\gamma -1}+ \frac{P_{1}V_{1}-P_{2}V_{2}}{n-1}

  =\left [ \frac{\gamma -n}{\gamma -1} \right ]\times \delta W

  =\left [ \frac{1.4 -1.25}{1.4 -1} \right ]\times 527.200

  = 197.7 kJ

6 0
3 years ago
A pump with a power of 5 kW (pump power, and not useful pump power) and an efficiency of 72 percent is used to pump water from a
almond37 [142]

Answer:

a) The mass flow rate of water is 14.683 kilograms per second.

b) The pressure difference across the pump is 245.175 kilopascals.

Explanation:

a) Let suppose that pump works at steady state. The mass flow rate of the water (\dot m), in kilograms per second, is determined by following formula:

\dot m = \frac{\eta \cdot \dot W}{g\cdot H} (1)

Where:

\dot W - Pump power, in watts.

\eta - Efficiency, no unit.

g - Gravitational acceleration, in meters per square second.

H - Hydrostatic column, in meters.

If we know that \eta = 0.72, \dot W = 5000\,W, g = 9.807\,\frac{m}{s^{2}} and H = 25\,m, then the mass flow rate of water is:

\dot m = 14.683\,\frac{kg}{s}

The mass flow rate of water is 14.683 kilograms per second.

b) The pressure difference across the pump (\Delta P), in pascals, is determined by this equation:

\Delta P = \rho\cdot g\cdot H (2)

Where \rho is the density of water, in kilograms per cubic meter.

If we know that \rho = 1000\,\frac{kg}{m^{3}}, g = 9.807\,\frac{m}{s^{2}} and H = 25\,m, then the pressure difference is:

\Delta P = 245175\,Pa

The pressure difference across the pump is 245.175 kilopascals.

4 0
3 years ago
4. Which 2D shape on the left would be used to make the 3D shape on the right? (1 pt.)
dexar [7]

it would be a bc its a sqare?well 3d is like you can say a cube 2d is like flat

Explanation:

7 0
2 years ago
The force on a cutting tool are 2600N vertically downward and 2100 horizontal. Determine the resultant force acting on the tool
kolezko [41]

Answer & Explanation:

"The force <em>on a cutting tool</em> are 2600N vertically downward" sounds a little unusual, since most of the time, the tool is above the object to be cut in such a way that the force acting "ON the tool" is upwards.  We will accept the statement as it is (downwards).

Since the two forces are acting at right angles to each other, the resultant can be found using Pythagoras theorem, namely

resultant = sqrt(2600^2+2100^2) = 3342 N (approx.)

The angle can be found using the arcTangent function, or

angle = arcTangent(2600/2100) = 51.07 degrees below the horizontal, since the 2600 N force is acting downwards.

3 0
3 years ago
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