Answer:
27009.56 mm
Explanation:
Given:
Diameter of the aluminium alloy bar, d = 12.5 mm
Length of the bar, L = 27 m = 27 × 10³ mm
Tensile force, P = 3 KN = 3 × 10³ N
Elastic modulus of the bar, E = 69 GPa = 69 × 10³ N/mm²
Now,
for the uniaxial loading, the elongation or the change in length (δ) due to the applied load is given as:
where, A is the area of the cross-section
or
or
A = 122.718 mm²
on substituting the respective values in the formula, we get
or
δ = 9.56 mm
Hence, the length after the force is applied = L + δ = 27000 + 9.56
= 27009.56 mm
Answer:
b). False
Explanation:
A refractory material is a type of material that can withstand high temperatures without loosing its strength. They are used in reactors, furnaces, kilns, etc.
Refractory materials are certain super alloys and ceramics materials.
Properties of refractory materials :
1. Refractory materials have high melting point.
2.They acts barriers between high heat zone and low heat zone.
3. The specific heat of refractory material is very low.
4. Refractories that have high bulk densities are better in quality.
Hence, Refractory materials have a very high melting temperature.
Answer:
4.2·10⁷
Explanation:
Exponents are added when multiplying:
(a^b)(a^c) = a^(b+c)
1.15·10⁵ × 3.65·10² ≈ 4.2·10⁷
_____
Your calculator is designed to work with scientific notation. Scientific or graphing calculators can also display their output in scientific notation. A spreadsheet can also perform this calculation for you and display the result in the required format.
Calculators and spreadsheets sometimes use "E" in place of "×10^". That is, 4.2E7 means 4.2×10^7.
Answer:
The code will be:
#include <stdio.h>
#include <stdlib.h>
main () {
double weight, shippingCharge, rate, segments;
int distance;
printf("Enter the weight: \n");
scanf("%lf", &weight);
printf("Enter the distance: \n");
scanf("%i", &distance);
if (weight <= 10) {
printf("Rate is $3.00 \n");
rate = 3;
} else {
printf("Rate is $5.00 \n");
rate = 5;
}
if (distance % 500 == 0) {
segments = distance / 500;
} else {
segments = distance / 500 + 1;
}
shippingCharge = rate * segments;
if (distance >1000) {
shippingCharge = shippingCharge + 10;
}
printf("Your shipping charge is $%lf\n", shippingCharge);
system ("pause");
}
