Answer:
hello some data related to your question is missing attached below is the missing data
answer : 63700 Ib/hr
Explanation:
Given data :
Limestone mix : consists of 94% CaCO3 and 6% inert material
Actual feed rate = 36,000 Ib/hr
SO2 in flue gas = 20,314 Ib/hr
FGD efficiency = 97%
resulting sludge contains 58% solids
<u>Calculate the Total sludge production rate </u>
First : determine SO2 removed in sludge
= 0.97 * 20314
= 19704.58 Ib/hr
next : moles of SO2 removed
= 19704.58 / 64 Ib/ Ib mol
= 307.88 Ib mol / hr
also moles of CaSO3 produced = 307.88 Ib mol / hr
mass of CaSO3 = 307.88 * 120 = 36946.09 Ib/hr
Therefore Total sludge production rate
= 36946.09 / 0.58
= 63700.15 Ib/hr
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Answer:
Investigué un poco y descubrí algunas cosas sorprendentes sobre los patos.Espero que los encuentres interesantes:Las aves acuáticas como los patos pueden mantener la diversidad de otros organismos, controlar las plagas, ser bioindicadores efectivos de las condiciones ecológicas y actuar como centinelas de posibles brotes de enfermedades. También proporcionan importantes aprovisionamientos (carne, plumas, huevos, etc.) y servicios culturales a las sociedades indígenas y occidentalizadas.La ubicuidad a menudo ridiculizada de los patos los convierte en vehículos ideales para transportar semillas de un lugar a otro, y eso significa humedales y biodiversidad más saludables para el beneficio de todas las aves y la vida silvestre.Sabías ? :Los patos ayudan al medio ambiente porque limpian los químicos del agua para que sus amigos y otros animales no mueran y se enfermen gravemente.
Explanation:
Engineering requires a lot of school
Answer: 150m
Explanation:
The following can be depicted from the question:
Dimensions of outer walls = 9.7m × 14.7m.
Thickness of the wall = 0.30 m
Therefore, the plinth area of the building will be:
= (9.7 + 0.30/2 + 0.30/2) × (14.7 × 0.30/2 + 0.30/2)
= 10 × 15
= 150m
Answer:
The correct answer is A : Orientation dependence of normal and shear stresses at a point in mechanical members
Explanation:
Since we know that in a general element of any loaded object the normal and shearing stresses vary in the whole body which can be mathematically represented as
![\sigma _{x'x'}=\frac{\sigma _{xx}+\sigma _{yy}}{2}+\frac{\sigma _{xx}-\sigma _{yy}}{2}cos(2\theta )+\tau _{xy}sin(2\theta )](https://tex.z-dn.net/?f=%5Csigma%20_%7Bx%27x%27%7D%3D%5Cfrac%7B%5Csigma%20_%7Bxx%7D%2B%5Csigma%20_%7Byy%7D%7D%7B2%7D%2B%5Cfrac%7B%5Csigma%20_%7Bxx%7D-%5Csigma%20_%7Byy%7D%7D%7B2%7Dcos%282%5Ctheta%20%29%2B%5Ctau%20_%7Bxy%7Dsin%282%5Ctheta%20%29)
And ![\tau _{x'x'}=-\frac{\sigma _{xx}-\sigma _{yy}}{2}sin(2\theta )+\tau _{xy}cos(2\theta )](https://tex.z-dn.net/?f=%5Ctau%20_%7Bx%27x%27%7D%3D-%5Cfrac%7B%5Csigma%20_%7Bxx%7D-%5Csigma%20_%7Byy%7D%7D%7B2%7Dsin%282%5Ctheta%20%29%2B%5Ctau%20_%7Bxy%7Dcos%282%5Ctheta%20%29)
Mohr's circle is the graphical representation of the variation represented by the above 2 formulae in the general oriented element of a body that is under stresses.
The Mohr circle is graphically displayed in the attached figure.