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Aleksandr [31]
3 years ago
14

Study the diagram below and answer these questions 1-6:

Chemistry
2 answers:
grandymaker [24]3 years ago
6 0
N=1 shell contains 2 electrons.
n=2 shell contains 5 electrons.
n=2 is the outermost shell. Therefore there were 5 electrons before sharing.
6 electrons are being shared between 2 nitrogen atoms.
Pair of electrons form a covalent bond. Therefore 3 pair of electrons will form 3 bonds.
irakobra [83]3 years ago
5 0

Explanation:

When n = 1 then it means the first shell of an atom whereas n = 2 means the second shell of an atom and so on.

As every atom consists of three sub-atomic particles which are protons, neutrons and electrons.

Protons and neutrons reside inside the nucleus of an atom and electrons revolve outside the nucleus of the atom.

A covalent bond is defined as the bond formed by sharing of electrons between the two combining atoms.

Therefore, the given questions are answered as follows.

  • There are 2 electrons in the n = 1 shell.
  • There are 5 electrons in its n = 2 shell.
  • There are 5 electrons in nitrogen's outer shell before sharing electrons.
  • 6 electrons are being shared between the two nitrogen atoms.
  • Covalent bonds exist between the two nitrogen atoms.
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The K a of propanoic acid ( C 2 H 5 COOH ) is 1.34 × 10 − 5 . Calculate the pH of the solution and the concentrations of C 2 H 5
Zigmanuir [339]

Answer:

2.62.

Explanation:

Okay let us first write the parameters in the question in question above out. We are given the ka value of propanoic acid, C2H5COOH to be equals to 1.34 × 10^- 5. Also, we are given the value for the initial concentration of propanoic acid to be 0.441 M.

So, let us delve right into the solution to the question and we will be starting by writting the equation below;

C2H5COOH <--------> H^+ + C2H5COO^-.

Please note that this Reaction is a reversible Reaction.

Therefore, the basic things about acid is its great tendency to release Hydrogen ion in an aqeous solution.

So, we will be taken equation above and correspond it with the time and Concentration.

C2H5COOH <----> H^+ C2H5COO^-.

Initial concentration of the C2H5COOH = 0.441 M and the initial concentration of H^+ and C2H5COO^- are both zero.

So, after a time, t, concentration of C2H5COOH= 0.441 - x and at that time the concentration of H^+ and C2H5COO^- are both x and x respectively.

Hence, Ka = [C2H5COO^-] [H^+]/ C2H5COOH. -----------------------(**).

Therefore, slotting in the values from above into equation (**), we have;

1.34 × 10^-5 = [x] [x]/ [0.441 - x].

1.34 × 10^-5= x^2/ [0.441 - x].

x^2 = 1.34 × 10^-5(0.441) - 1.34 × 10^-5x.

x^2 + 1.34 × 10^-5x - 5.91× 10^-6.

x = 2.4×10^-3.

Hence, the concentration of the propanoic acid at time, t= 0.441 - 2.4 ×10^-3.

==> 0.44 M.

pH = -log [H^+].

Then, we have; pH= - log[2.4× 10^-3].

pH= 2.62.

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