Which if the following questions can be answered by science?

Chemistry

1 answer:

Vladimir79 [104]3 years ago

8 0

Answer:

Need the choices before i can give answers thanks

Explanation:

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A 0.1873 g sample of a pure, solid acid, H2X (a diprotic acid) was dissolved in water and titrated with 0.1052 M NaOH solution.

puteri [66]

Answer:

We need 41.8 mL of NaOH

Explanation:

Step 1: Data given

Mass of H2X = 0.1873 grams

Molarity of NaOH solution = 0.1052 M

Molar mass of H2X = 85.00 g/mol

Step 2: The balanced equation

H2X (aq) +2 NaOH (aq) → Na2X (aq) + 2H2O(l)

Step 3: Calculate moles of H2X

Moles H2X = mass H2X / Molar mass H2X

Moles H2X = 0.1873 grams / 85.00 g/mol

Moles H2X = 0.0022 moles

Step 4: Calculate moles of NaOH

For 1 mol H2X we need 2 moles NaOH to produce 1 mole of Na2X and 2 moles of H2O

For 0.0022 moles of H2X we need 0.0044 moles of NaOH

Step 5: Calculate volume of NaOH

Volume of NaOH = moles of NaOH / molarity of NaOH

Volume of NaOH = 0.0044 moles / 0.1052 M

Volume NaOH = 0.0418 L = 41.8 mL

We need 41.8 mL of NaOH

6 0

3 years ago

What is the length of one mole of the typical cell phone that is approximately 15 cm in length?

Salsk061 [2.6K]

i dont know how to remove my answer so ignore this

4 0

3 years ago

Read 2 more answers

The boiling point of water is 1000C.

sergejj [24]

Answer:

a) The heat which we supply to water during boiling is used to overcome these forces of attraction between the particles so that they become totally free and change into a gas. This latent heat does not increase the kinetic energy of water particles and hence no rise in temperature takes place during the boiling of water.

b) Steam produces more severe burns than boiling water even though both are at 100oC because steam contains more heat, in the form of latent heat, than boiling water.

Explanation:

i hope this will help u

7 0

3 years ago

For the reaction 2NH3(g) + 2O2(g)N2O(g) + 3H2O(l) H° = -683.1 kJ and S° = -365.6 J/K The standard free energy change for the rea

BlackZzzverrR [31]

Answer:

$\Delta G^{0}$ = -457.9 kJ and reaction is product favored.