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Makovka662 [10]
4 years ago
7

Describe how the atoms in Calcium Chloride obey the octet rule.

Chemistry
1 answer:
Anit [1.1K]4 years ago
8 0
Calcium can lose 2 electrons hence the +2 charge. Chlorine can gain 1 electron hence the charge -1. when they transfer electrons there is an extra electron remaining this goes to another chlorine atom. That is why the chemical equation is CaCl2. Calcium gives two electrons to two different chlorine atoms.
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PLEASE HELP WILL GIVE BRAINLIEST
nevsk [136]

Answer:

16. Option c.

Explanation:

The reaction is:

C₈H₁₈ + O₂  →  CO₂ + H₂O

Let's count, we have 8 C, 18 H and 2 O in reactant side

We have 1 C, 2 H and 3 O  in product side

In order to balance the C, we add 8 to CO₂ and to balance the H, we add a 9 to H₂O

Now we have 8 C on both sides and 18 H On both sides. Finally we have 25 O on product side.

C₈H₁₈ + O₂  →  8CO₂ + 9H₂O

To balance the O in product side we must add 25/2, but as it is a rational number, we must multiply x2 to get an integer number (x2 in all the stoichiometry). The balanced reaction is :

2C₈H₁₈ + 25O₂  →  16CO₂ + 18H₂O

with 16 C, 36 H and 50 O, on both sides

7 0
3 years ago
Read 2 more answers
If NaCl has a mass of 3.2g, what is the volume of chlorine gas at STP?
Shalnov [3]

Hey there!

Molar mass NaCl = 58.44 g/mol

58.44 g ----------------- 22.4 ( at STP )

3.2 g -------------------- Volume ??

Volume = ( 3.2 x 22.4 )  / 58.44

Volume = 71.68 / 58.44

Volume = 1.226 L

Hope this helps!

5 0
3 years ago
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Which is a potential benefit of genetic engineering in agriculture? higher levels of toxins disruption of other genes increased
MrMuchimi

Answer:

increase in the size of fruits and vegetables

8 0
3 years ago
If you doubled the volume of a sample of gas and
Dimas [21]

Answer:

1125mL

Explanation:

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3 0
3 years ago
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The Haber process can be used to produce ammonia (NH3) from hydrogen gas (H2) and nitrogen gas (N2). The balanced equation for t
kotykmax [81]

Answer:

B

Explanation:

We are given that ammonia can be produced from hydrogen gas and nitrogen gas according to the equation:

\displaystyle 3\text{H$_2$} +  \text{N$_2$} \longrightarrow 2\text{NH$_3$}

We want to determine the mass of hydrogen gas that must have reacted if 0.575 g of NH₃ was produced.

To do so, we can convert from grams of NH₃ to moles of NH₃, moles of NH₃ to moles of H₂, and moles of H₂ to grams of H₂.

We are given that the molar masses of NH₃ and H₂ are 17.03 g/mol and 2.0158 g/mol, respectively.

From the equation, we can see that two moles of NH₃ is produced from every three moles of H₂.

With the initial value, perform dimensional analysis:

\displaystyle \begin{aligned} 0.575\text{ g NH$_3$}& \cdot \frac{1\text{ mol NH$_3$}}{17.03\text{ g NH$_3$}} \cdot\frac{3\text{ mol H$_2$}}{2\text{ mol NH$_3$}} \cdot \frac{2.0158\text{ g H$_2$}}{1\text{ mol H$_2$}} \\ \\ & =  0.102\text{ g H$_2$}\end{aligned}

*Assuming 100% efficiency.

Our final answer should have three significant figures. (The first term has three, the second term has four (the one is exact), the third term is exact, and the fourth term has five. Hence, the product should have only three.)

In conclusion, our answer is B.

3 0
3 years ago
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