The product formed when HCl and CH2Cl2 react is CH4
H
H-C- H methane structure
H
HCl react with CH2Cl2 to form methane (CH4) and chlorine gas(Cl2)
that is,
2HCl(g) + CH2Cl2(l) = CH4 (g) +2Cl2 (g)
Answer:
Explanation:
There are three types of interactions involved between the particles when solution are formed.
1 : Solute - solute interaction:
2 : Solute - solvent interaction:
3 : Solvent - solvent interaction:
1 : Solute - solute interaction:
It is the inter-molecular attraction between the solute particles.
2 : Solute - solvent interaction:
It involve the inter-molecular attraction between solvent and solute particles.
3 : Solvent - solvent interaction:
It involve the intermolecular attraction between solvent particles.
Solutions are formed if the intermolecular attraction between solute particles are similar to the attraction between solvent particles.
Exothermic process:
The process will exothermic when solute solvent bonds are formed with the release of energy and energy required to brake the solute-solute particles and solvent solvent particles are less.
Endothermic process:
The process will be endothermic when energy required to break the solute-solute particles and solvent solvent particles are higher than energy released when solute solvent bonds are formed .
From the given equations, the combustion reaction is;
C₄H₁₂ + 7O₂ --> 4CO₂ + 6H₂O
Combustion reactions are when organic compounds react with O₂ to produce water and CO₂. From the given reactions, C₄H₁₂ is an organic compound that reacts with O₂ to produce water and CO₂.
Therefore this is the only reaction that follows the general equation for combustion.
Answer:
55.18 L
Explanation:
First we convert 113.4 g of NO₂ into moles, using its molar mass:
- 113.4 g ÷ 46 g/mol = 2.465 mol
Then we<u> use the PV=nRT formula</u>, where:
- P = 1atm & T = 273K (This means STP)
- R = 0.082 atm·L·mol⁻¹·K⁻¹
Input the data:
- 1 atm * V = 2.465 mol * 0.082atm·L·mol⁻¹·K⁻¹ * 273 K
And <u>solve for V</u>:
Answer:
PCl3
Explanation:
The molecular formular of a compound shows the exact number of atoms of elements present in the compound. In this illustration, there is one atom of P and 3 atoms of Cl.
The formular is given as; PCl3
