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alexandr402 [8]
3 years ago
11

Using the model,what is the mass of the atom pictured? A)3amu B)5amu C)7amu D)9amu

Chemistry
2 answers:
spayn [35]3 years ago
6 0

Answer:

7amu

Explanation:

Atoms are composed of three particles.  The proton, neutron, and electron.  

The mass of the atom in amu is just the number of protons and neutrons in the nucleolus since they both have a mass of about 1 amu.  Electrons are not counted since they have an incredibly small mass that ultimately does not matter.  

This atom has 3 protons (positively charged particle) and 4 neutrons (particle with no charge) which together gives a mass of 7 amu.

DedPeter [7]3 years ago
5 0

Answer:

with 20 protons (p=20) and 22 neutrons (n=22)? 47 ... Listed below are the charges and masses of four ... a) +2,2 amu c ) +1, 1 amu least b) ... pudding” Model.

Explanation:

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BALANCE the following equations then write the NET IONIC EQUATION for each one: ____Ni(NO​ 3​ )​ 2​​(aq)​ + ____NaOH ​(aq)​ ​→ ​
Karo-lina-s [1.5K]

Answer:

Ni(NO3)2 + 2NaOH → Ni(OH)2 + 2NaNO3

NET IONIC EQUATION :

Ni +2(aq)  + 2(NO3) -1(aq)  + 2Na +1(aq)  + 2OH -1(aq)

→ Ni(OH)2 (s)  + 2Na +1(aq)  +  2(NO3) -1(aq)

sorry there is no space to write the reaction in one line...

8 0
3 years ago
Two gases are combined and sealed in a 2.0 L container. The 3.0 L of argon gas and 1.0 L of xenon gas each exert 1.00 atm pressu
mariarad [96]

Answer:

Unless they chemically react with each other, the individual gases in a mixture of gases do not affect each other’s pressure. Each individual gas in a mixture exerts the same pressure that it would exert if it were present alone in the container . The pressure exerted by each individual gas in a mixture is called its partial pressure.

Explanation:

7 0
3 years ago
What is ΔE in kJ for a system that receives 1.79 kJ of heat from surroundings and has 4.51 kcal of work done on it at the same t
kenny6666 [7]

Answer: 20.7 kJ

Explanation:

According to first law of thermodynamics:

\Delta E=q+w

\Delta E=Change in internal energy

q = heat absorbed or released

w = work done or by the system

w = work done on the system=-P\Delta V  {Work is done on the system is positive as the final volume is lesser than initial volume}

w = 4.51 kcal = 4.51\times 4.184kJ=18.9kJ    (1kcal = 4.184kJ)

q = +1.79 kJ   {Heat absorbed by the system is positive}

\Delta E=+1.79+(18.9)=20.7kJ

Thus \Delta E for a system that receives 1.79 kJ of heat from surroundings and has 4.51 kcal of work done on it at the same time is 20.7 kJ

4 0
3 years ago
A stock solution of HNO3 is prepared and found to contain 13.5 M of HNO3. If 25.0 mL of the stock solution is diluted to a final
salantis [7]

Answer : The correct option is, (C) 0.675 M

Explanation :

Using neutralization law,

M_1V_1=M_2V_2

where,

M_1 = concentration of HNO_3 = 13.5 M

M_2 = concentration of diluted solution = ?

V_1 = volume of HNO_3 = 25.0 ml  = 0.0250 L

conversion used : (1 L = 1000 mL)

V_2 = volume of diluted solution = 0.500 L

Now put all the given values in the above law, we get the concentration of the diluted solution.

13.5M\times 0.0250L=M_2\times 0.500L

M_2=0.675M

Therefore, the concentration of the diluted solution is 0.675 M

8 0
3 years ago
For the following amino acids, draw a triangle around the amine group, draw a square around the carboxyl and circle the side gro
mylen [45]

hooc are carboxyl groups

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4 0
3 years ago
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