Answer:
Explanation:
Hello,
In this case, the combustion of methane is shown below:
And has a heat of combustion of −890.8 kJ/mol, for which the burnt moles are:
Whereas is consider the total released heat to the surroundings (negative as it is exiting heat) and the aforementioned heat of combustion. Then, by using the ideal gas equation, we are able to compute the volume at 25 °C (298K) and 745 torr (0.98 atm) that must be measured:
Best regards.
5CO2 should be in the blank spot.
the reaction would be 7
From the calculations performed, the Kb of the reaction is 9.9 * 10^-10
<h3>What is Kb?</h3>
The term Kb refers to the base dissociation constant of a solution. We have the following information from the question;
pH of the solution = 8.60
concentration of p-toluidine = 0.016-M
Recall that pOH = 14 - pH
pOH = 14 - 8.60 = 5.4
[OH] = Antilog (-5.4) = 3.98 * 10^-6 M
We have to set up the ICE table;
CH3C6H4NH2(aq) + H2O(l) ⇄ CH3C6H4NH3^+(aq) + OH^-(aq)
I 0.016 0 0
C -x +x +x
E 0.016 - x 3.98 * 10^-6 3.98 * 10^-6
Hence;
Kb = [3.98 * 10^-6]^2/[0.016 - 3.98 * 10^-6]
Kb = 9.9 * 10^-10
Learn more about Kb: brainly.com/question/12726841
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