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mamaluj [8]
3 years ago
6

Lets say you were doing an experiment on two different chemicals in two different test tubes. One chemical is giving off oxygen

gas or hydrogen gas the other is giving off carbon dioxide gas. What one test could you do in each test tube that would prove which is giving of the oxygen or hydrogen an which is giving off the carbon dioxide
Chemistry
1 answer:
boyakko [2]3 years ago
5 0

Answer:

Tests for gases

Hydrogen, oxygen, carbon dioxide, ammonia and chlorine can be identified using different tests.

Hydrogen. A lighted wooden splint makes a popping sound in a test tube of hydrogen.

Oxygen. A glowing wooden splint relights in a test tube of oxygen.

hope it will help

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A reaction is started with both reactants and products and proceeds in the reverse direction to reach equilibrium. Which of the
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Answer:

Option A

Explanation:

A) Yes. The reaction reaches equilibrium when the rate of reaction of the reverse reaction is equal to the rate of the forward reaction , then the only cause for the reverse reaction to be favoured is that the initial rate of the reverse was greater than the forward one.

B) No. The rate constant of the reverse reaction can be greater than the forward one  but the rate also depends on concentrations, thus a reverse reaction with greater rate constant can result in the net reaction proceeding in the forward reaction, the reverse reaction or be at equilibrium depending on the concentrations or reactants and products

C) No. A lower activation energy means a higher rate constant , but a higher rate constant does not mean that the net reaction will proceed to the reactants ( see point B)

D) No. The energy changes determine conditions under thermodynamic equilibrium and therefore the net direction of the reaction will depend on the temperature and concentrations of reactants and products with respect to the equilibrium conditions.

6 0
3 years ago
The average atomic masses of some elements may vary, depending upon the sources of their ores. Naturally occurring boron consist
frez [133]
Sorry I don’t know but good luck!
6 0
3 years ago
Read 2 more answers
Can someone please please help me out ?
GarryVolchara [31]

Answer:

4.823 x 10^-19 J

Explanation:

Energy is calculated by E = hv where h - Planck's constant in joule.s

v - frequency.

in this particular question the wave length is 4.12 x 10^-7 m. to exhaustively use this we need a relation between wave length & frequency. c=wv where C is approximately 3 x 10^8m/s

-v = c/w = 3x10^8m/s / 4.12 x 10^-7m = 7.28 x 10^14 Hz or 1/sec

now we can simply use Planck's constant in E=hv =

(6.626 x 10^-34) x (7.28 x 10^14Hz) = 4.823 x 10^-19 J.

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What determines the speed at which a particle of matter moves
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The force exerted on it.

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