Answer:
The frequency of this light is 
.
Explanation:
Wavelength of the light = 
Speed of the light = c = 
Frequency of the light = 
The frequency of this light is .
Answer:
<h3>Hlo there !! </h3>
<u>One mole of any substance contains 6.022*1023 structural units (atoms, molecules, ions, etc.). This number is known as the Avogadro constant.</u>
<u>One mole of any substance contains 6.022*1023 structural units (atoms, molecules, ions, etc.). This number is known as the Avogadro constant.So 1.04*107 mol of Al contains 1.40*107 * 6.022*1023 = 8.43*1030 structural units (in case of Al – atoms).</u>
<h3><u>8.43*1030 particles Al.</u></h3>
Explanation:
<h3>Hope this helps !!</h3>
Answer:
Explanation:
In this question, we wish to find the missing nuclei for the equation:
In order to find the missing species, we need to use the charge and mass balance law. That is, the mass should be conserved: the total mass on the left-hand side with respect to the arrow should be equal to the total mass on the right-hand side with respect to the arrow:
Notice from here that:
So far we know that the mass of X is 4. Similarly, we apply the law of charge conservation. The total charge should be conserved:
From here:
We have a particle:
Looking at the periodic table, an atom with Z = 2 corresponds to helium. This can also be written as an alpha particle:
Answer:
D
Explanation:
To answer this question, we will need to write the dissociation equation of aluminum trichloride.
AlCl3 ——-> Al3+ + 3Cl-
It can be seen that when aluminum chloride dissociates, it gives one mole of aluminum ion and three moles of the chloride ion.
From here we can see that the concentration of the aluminum chloride equals that of the aluminum ion while that of the chloride ion is thrice that of the aluminum chloride. This means we simply multiply 0.12M by 3 to get the molarity of the chloride ion while that of the aluminum ion remains the same
