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Vilka [71]
3 years ago
8

Sunlight Grass → Rabbit + Snake

Chemistry
2 answers:
Bezzdna [24]3 years ago
7 0

Answer:

The abiotic factor is <u>S</u><u>u</u><u>n</u><u>l</u><u>i</u><u>g</u><u>h</u><u>t</u><u>.</u>

Savatey [412]3 years ago
4 0
I think is sunlights I think that
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In 1786 Luigi Galvani developed the theory of: a Static electricity b Reciprocal electricity c Animal electricity d battery elec
Ostrovityanka [42]
Static electricity jrbfbfjfbfbbfbfjfngbffjfbfbffjnfnfnf
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3 years ago
How many moles of Ammonium Sulfate can be made from 30.0mol of NH3? 2NH3 + H2SO4 --&gt; (NH4)2SO4
BartSMP [9]

Answer: 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

Explanation:

The balanced chemical reaction is :

2NH_3+H_2SO_4\rightarrow (NH_4)_2SO_4

According to stoichiometry :

2 moles of NH_3 give = 1 mole of (NH_4)_2SO_4

Thus 30.0 moles of NH_3 will give =\frac{1}{2}\times 30.0=15.0moles  of (NH_4)_2SO_4

Thus 15.0 moles of (NH_4)_2SO_4 are formed from  30.0 mol of NH_3

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3 years ago
All the food chains in an ecosystem that are connected together form a ?
joja [24]

All food chain in an ecosystem that are connected to each other forms a food web....

Therefore the answer is food web

5 0
3 years ago
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Based on the article "Will the real atomic model please stand up?,” describe one major change that occurred in the development o
nydimaria [60]
I don't know this article, but I do know some major changes: first, the change from the plum pudding model (no nucleus, just electrons) to the gold foil experiment, which had Rutherford shoot alpha particles at a sheet of gold only to find them rebounding, proving the existence of a positively charged mass, i.e a nucleus, in the atom. However, this changed again when Bohr realized that the negatively charged electrons should be attracted to the positively charged center, so that there must be something else inside the nucleus. 
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You are given sodium acetate, 1m hcl, nahco3 and na2co3. Determine which of these four you would need and then show calculations
valentina_108 [34]

solution:

the given compounds are sodium acetate, 1M HCL,NaHCO₃ and Na2CO₃

pH of the buffer solution is 4.7

the value of pKa of sodium bicarbonate is 6.37

the value of pKa of acetic acid is 4.7

calculate concentration of acetic acid by using the following forumula

pH=pKa+lag[salt]/[acid]

substitute the pH and Pka values in the formula.

4.7=4.7+log[salt]/[acid]

log[salt]/[acid]=0

thus, the concentration ratio of the salt and acid should be equal to each other.

Thus, concentration of sodium acetate is 0.05M

Concentration of sodium acetate= concentration of acid

= 0.05M

Volume of the buffer solution is 100mL

The buffer solution can be prepared as 0.05M of 50mL sodium acetate will react with 0.05M of 50mL of 0.05M of HCL.

The chemical equation for neutralization of the weak base with strong can be represented as show as

CH₃COONa+HCL-->CH₃COOH+NaCL


5 0
3 years ago
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