Answer:
one in a 2s orbital
Explanation:
Because of the peak near the nucleus in the 2s curve there is a higher probability of finding a 2s within 4 Å of the nucleus. In a multi-electron atom an electron in a 2s orbital will have a lower energy than one in a 2p orbital
Answer: The mole ratio of oxygen to pentane for the combustion of pentane is 8 : 1.
Explanation: The given reaction is a type of combustion reaction.
Combustion reaction is a reaction in which a hydrocarbon reacts with oxygen gas to produce water and carbon dioxide gas.
For the reaction of pentane with oxygen, the balanced equation would be:
In the reaction, 1 mole of 
reacts with 8 moles of 
gas.
Thus giving us the mole ratio as
Oxygen : Pentane = 8 : 1
PV = nRT
P is pressure, V is volume, n is number of moles, R is the gas constant, T is temperature in K
(2.85 atm)(12.5 L) = (n)(.08206)(27 C + 273)
n = 1.45 moles x 35.45 grams / mol Cl2 = 51.3 grams
A. high potential energy and zero kinetic energy.
Answer:
Explanation:
molecular weight of N₂H₄ is as follows
2 x 14 + 4 x 1 = 32
so 32 gram of N₂H₄ is equal to one mole of N₂H₄
25 gram of N₂H₄ will be equal to 25 / 32 mole of N₂H₄
so numerical quantity needed to convert grams of N₂H₄ to mole is
1 / 32 or .03125 . This number needs to be multiplied with grams of N₂H₄
to convert it to number of moles.
