Answer:
Find the dimension of each and every quantity in all the options to check whether they are the same or not. We can use any one formula of each identity to find its dimension.
Complete step by step solution:
To find the dimension of a quantity, we can use any formula related to that quantity but we will use the easiest ones to save time.
Force-
from Newton’s law of motion,
F=maF=ma
Dimension of force =[M][LT−2]=[MLT−2]=[M][LT−2]=[MLT−2]
Work done-
W=F×sW=F×s
Dimension of work=[MLT−2][L]=[ML2T−2]=[MLT−2][L]=[ML2T−2]
Momentum-
p=mvp=mv
Dimension of momentum=[M][LT1]=[MLT−1]=[M][LT1]=[MLT−1]
Impulse-
I=F×tI=F×t
Dimension of impulse=[MLT−2][T]=[
Answer:
124.52 mL
Explanation:
from Boyle's Law,
PV = P'V' ................... Equation 1
Where P = Initial pressure of the gas, V = Initial volume of the gas, P' = Final pressure of the gas, V' = Final volume of the gas.
make V' the subject of the equation.
V' = PV/P'............. Equation 2
Given: P = 267 torr = (267×0.00131) = 0.34977 atm, V = 356 mL, P' = 1 atm
Substitute into equation 2
V' = (0.34977×356)/1
V' = 124.52 mL.
Hence the new volume of the balloon = 124.52 mL
The displacement of Edward in the westerly direction is determined as 338.32 km.
<h3>What is displacement of Edward?</h3>
The displacement of Edward can be determined from different methods of vector addition. The method applied here is triangular method.
The angle between the 200 km north west and 150 km west = 60 + 90 = 150⁰
The displacement is the side of the triangle facing 150⁰ = R
R² = a² + b² - 2abcosR
R² = 150² + 200² - (2x 150 x 200)xcos(150)
R² = 62,500 - (-51,961.52)
R² = 114,461.52
R = 338.32 km
Learn more about displacement here: brainly.com/question/321442
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A :-) for this question , we should apply
a = v - u by t
Given - u = 4.77 m/s
v = 23.5 m/s
t = 5.18 m/s
Solution -
a = v - u by t
a = 23.5 - 4.77
a = 28.27 m/s^2
.:. The acceleration is 28.27 m/s^2
