Answer:
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Answer:
The strength of the electric field is
.
Explanation:
Given that,
Speed ![v= 5.05\times10^{5}\ m/s](https://tex.z-dn.net/?f=v%3D%205.05%5Ctimes10%5E%7B5%7D%5C%20m%2Fs)
Time ![t= 3.90\times10^{-7}\ s](https://tex.z-dn.net/?f=t%3D%203.90%5Ctimes10%5E%7B-7%7D%5C%20s)
Angle = 45°
We need to calculate the acceleration
Using equation of motion
![v = u+at](https://tex.z-dn.net/?f=v%20%3D%20u%2Bat)
![5.05\times10^{5}=0+a\times3.90\times10^{-7}](https://tex.z-dn.net/?f=5.05%5Ctimes10%5E%7B5%7D%3D0%2Ba%5Ctimes3.90%5Ctimes10%5E%7B-7%7D)
![a =\dfrac{5.05\times10^{5}}{3.90\times10^{-7}}](https://tex.z-dn.net/?f=a%20%3D%5Cdfrac%7B5.05%5Ctimes10%5E%7B5%7D%7D%7B3.90%5Ctimes10%5E%7B-7%7D%7D)
![a=1.29\times10^{12}\ m/s^2](https://tex.z-dn.net/?f=a%3D1.29%5Ctimes10%5E%7B12%7D%5C%20m%2Fs%5E2)
We need to calculate the strength of the electric field
Using relation of newton's second law and electric force
![F= ma=qE](https://tex.z-dn.net/?f=F%3D%20ma%3DqE)
![ma = qE](https://tex.z-dn.net/?f=ma%20%3D%20qE)
![E=\dfrac{ma}{q}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7Bma%7D%7Bq%7D)
Put the value into the formula
![E=\dfrac{1.67\times10^{-27}\times1.29\times10^{12}}{1.6\times10^{-19}}](https://tex.z-dn.net/?f=E%3D%5Cdfrac%7B1.67%5Ctimes10%5E%7B-27%7D%5Ctimes1.29%5Ctimes10%5E%7B12%7D%7D%7B1.6%5Ctimes10%5E%7B-19%7D%7D)
![E=1.35\times10^{4}\ N/C](https://tex.z-dn.net/?f=E%3D1.35%5Ctimes10%5E%7B4%7D%5C%20N%2FC)
Hence, The strength of the electric field is
.
<span>"A force is required to cause motion to deviate from a straight line.</span>
The ball can't reach the speed of 20 m/s in two seconds, unless you THROW it down from the window with a little bit of initial speed. If you just drop it, then the highest speed it can have after two seconds is 19.6 m/s .
If an object starts from rest and its speed after 2 seconds is 20 m/s, then its acceleration is 20/2 = 10 m/s^2 .
(Gravity on Earth is only 9.8 m/s^2.)
Answer:
The correct answer is B
Explanation:
To calculate the acceleration we must use Newton's second law
F = m a
a = F / m
To calculate the force we use the defined pressure and the radiation pressure for an absorbent surface
P = I / c absorbent surface
P = F / A
F / A = I / c
F = I A / c
The area of area of a circle is
A = π r²
We replace
F = I π r² / c
Let's calculate
F = 8.0 10⁻³ π (1.0 10⁻⁶)²/3 10⁸
F = 8.375 10⁻²³ N
Density is
ρ = m / V
m = ρ V
m = ρ (4/3 π r³)
m = 4500 (4/3 π (1 10⁻⁶)³)
m = 1,885 10⁻¹⁴ kg
Let's calculate the acceleration
a = 8.375 10⁻²³ / 1.885 10⁻¹⁴
a = 4.44 10⁻⁹ m/s² absorbent surface
The correct answer is B