Answer:
All of these three are polar molecules or ions
Explanation:
1) CO3 ^2-
It is a polar ion because it consists of one Oxygen atom and three carbon atoms so there is a substantial electroegativity difference between carbon and Oxygen due to which shared electrons are attracted more towards Oxygen creating partial negative charge on it and less towards carbon creating a partial positive charge on it, which makes the overall ion polar.
2) HCN
HCN is a polar molecule because there is substantial electronegativity difference between Carbon and Hydrogen as well as between Carbon and Nitrogen. Due to this negative charge is induced over Nitrogen because electronegativity of Nitrogen is 3.0 and positive charge on Carbon because its electronegativity is 2.5. The overall molecule is polar.
3) NO3^-1
Nitrate ion is also a polar molecule because there are three atoms of Oxygen and one atom of Nitrogen. There is substantial electronegativity difference between oxygen (3.44) and nitrogen (3.0) due to which partial positive charge is created on Nitrogen and partial negative charge created over three Oxygen atoms. The overall molecule is polar.
Hope it helps!
Answer:
![K_{c} = [\text{C}]^{2}[\text{[D]}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5B%5Ctext%7BC%7D%5D%5E%7B2%7D%5B%5Ctext%7B%5BD%5D%7D)
Explanation:
The general formula for an equilibrium constant expression is
![K_{c} = \dfrac{[\text{Products}]}{[\text{Reactants}]}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5Cdfrac%7B%5B%5Ctext%7BProducts%7D%5D%7D%7B%5B%5Ctext%7BReactants%7D%5D%7D)
Solids and liquids are not included in the equilibrium constant expression.
Thus, for this reaction,
![K_{c} = [\textbf{C}]^{\mathbf{2}}\textbf{[D]}](https://tex.z-dn.net/?f=K_%7Bc%7D%20%3D%20%5B%5Ctextbf%7BC%7D%5D%5E%7B%5Cmathbf%7B2%7D%7D%5Ctextbf%7B%5BD%5D%7D)
Answer is: elements in group 1 will lose electrons to obtain a noble gas structure. They will lose 1 electron.
For example ₃Li 1s²2s¹ will lose one electron from 2s oribtal to obtain helium structure ₂He 1s².
Or sodium ₁₁Na 1s²2s²2p⁶3s¹ will also lose one electron to obtain neon structure ₁₀Ne 1s²2s²2p⁶.
Balanced equation : 2Na+I₂⇒2NaI
<h3>Further explanation
</h3>
Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:
• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.
• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product
• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1
Reaction
Na+I₂⇒NaI
aNa+bI₂⇒NaI
Na, left=a, right=1⇒a=1
I, left=2b, right=1⇒2b=1⇒b=0.5
Equation becomes :
Na+0.5I₂⇒NaI x 2
2Na+I₂⇒2NaI
Explanation:
even I don't know this answer
but maybe you can solve it by putting the formula
