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antiseptic1488 [7]
3 years ago
13

Tin has ten stable isotopes. The heaviest, 124Sn, makes up 5.80% of naturally occuring tin atoms. How many atoms of 124Sn are pr

esent in 82.0 g of naturally occurring tin? What is the total mass of the 124Sn atoms in this sample?
Chemistry
1 answer:
matrenka [14]3 years ago
5 0

The average atomic mass of Sn is 118.71 g/mol

the percentage of heaviest Sn is 5.80%

the given mass of Sn is 82g

The total  moles of Sn will be = mass / atomic mass = 82/118.71=0.691

Total atoms of Sn in 82g = 6.023X10^{23}X0.691=4.16X10^{23}

the percentage of heaviest Sn is 5.80%

So the total atoms of Sn^{124} = 5.80% X 4.16X10^{23}

Total atoms of Sn^{124}=2.41X10^{22} atoms

the mass of Sn^{124} will be = \frac{2.41X10^{22}X124}{6.023X10^{23}}=4.96g

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