Enter an equation for the formation of NO2(g) from its elements in their standard states. Express your answer as a chemical equa
tion. Identify all of the phases in your answer.
1 answer:
The standard state of the elements Nitrogen and Oxygen are N2 and O2, knowing that they are diatomic elements. With that piece of information, the unbalanced equation for the formulation of NO2(g) should be as follows -
N2 + O2 ---> NO2
And if you include their states -
N2 ( g ) + O2 ( g ) ---> NO2 ( g )
To balance this chemical equation consider the number of reactants and products on other side of the equation. If you were to include a coefficient of one - half with respect to N2 on the reactant side, it would balance the reactants and products -
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1.95 or 2 is the molarity of a 45.3g sample of KNO3 (101g) dissolved in enough water to make a 0.225L solution.
The correct answer is option b
Explanation:
Data given:
mass of KN = 45.3 grams
volume = 0.225 litre
molarity =?
atomic mass of KNO3 = 101 grams/mole
molarity is calculated by using the formula:
molarity =
first the number of moles present in the given mass is calculated as:
number of moles =
number of moles =
0.44 moles of KNO3
Putting the values in the equation of molarity:
molarity =
molarity = 1.95
It can be taken as 2.
The molarity of the potassium nitrate solution is 2.
Answer:
Explanation:
Let's say the reaction is
R ⇌ 2P; endothermic
I like to consider heat as if it were a reactant or a product in a chemical equilibrium.
Another way to write the equilibrium would be
heat + R ⇌ 2P
According to Le Châtelier's Principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.
Let's consider each of the stresses in turn.
(i) Changing the temperature
If you want to increase the amount of product, you increase the temperature. The system will try to get rid of the added heat by shifting to the right, thus forming more product.
(ii) Changing the pressure
If R and P are liquids or solids or in aqueous solution, changing the pressure will have no effect. Something must be in the gas phase for a change in pressure to affect the position of equilibrium.
If P is a gas, the equilibrium is
heat + R ⇌ 2P(g)
Then, decreasing the pressure will produce more P. If you reduce the pressure, the system will respond by shifting to the right (the side with more gas molecules) to produce more P and bring the pressure back up
Explanation :
The balanced chemical reaction is,
The expression for the rates of consumption of the reactants are:
The rate of consumption of =
The rate of consumption of =
The rate of consumption of =
The expression for the rates of formation of the products are:
The rate of consumption of =
The rate of consumption of =