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GrogVix [38]
4 years ago
5

Enter an equation for the formation of NO2(g) from its elements in their standard states. Express your answer as a chemical equa

tion. Identify all of the phases in your answer.

Chemistry
1 answer:
kkurt [141]4 years ago
7 0

The standard state of the elements Nitrogen and Oxygen are N2 and O2, knowing that they are diatomic elements. With that piece of information, the unbalanced equation for the formulation of NO2(g) should be as follows -

N2 + O2 ---> NO2

And if you include their states -

N2 ( g ) + O2 ( g ) ---> NO2 ( g )

To balance this chemical equation consider the number of reactants and products on other side of the equation. If you were to include a coefficient of one - half with respect to N2 on the reactant side, it would balance the reactants and products -

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Consider the reaction below. CO(g) + Cl2(g) « COCl2(g) What is the most likely effect to the forward reaction if there is an inc
marysya [2.9K]
Answer: the reaction rate of the forward reaction increases (although it is not among the options shown).

Explanation:

1) The equation given is:

CO (g) + Cl₂ (g)  ⇄ COCl₂ (g)

2)  The forward reaction is:

CO (g) + Cl₂ (g)  → COCl₂ (g)

3) The stoichiometry is 1 mole + 1 mole → 1 mole

4) Analysis and conclusion:

The effect of change in the conditions of an equilibrium is foreseen using Le Chatelier's principle.

Le Chatelier's principle states that a system in equilibrium will act trying to compensate the distress applied to the system.

In this case, the distress is increase in pressure.

To compensate the increase in pressure the system must act by reducing the number of moles in the system. Since the forward reaction implies the conversion of two moles of reagents into one mole of product, the more the forward reaction progress the less the number of moles will be present in the system and so the more the compensation of the increase in pressure. So the forward raction is favored by the increase in pressure.

Favoring the forwar reaction means that its rate will incrase,

3 0
3 years ago
Read 2 more answers
Identify the solute with the highest van't Hoff factor. And how do you determine which one is highest?
german

Answer : The correct option is, (A) AlCl_3

Explanation :

Van't Hoff factor : It is defined as the ratio of the experimental value of the colligative property to the calculated value of the colligative property.

We can determine the van't Hoff factor by the association and dissociation of the compound.

(A) AlCl_3

It is an electrolyte that dissociates to give aluminum ion and chloride ion.

The dissociation of AlCl_3 will be,

AlCl_3\rightarrow Al^{3+}+3Cl^{-}

So, Van't Hoff factor = Number of solute particles = Al^{3+}+3Cl^{-} = 1 + 3 = 4

(B) KI

It is an electrolyte that dissociates to give potassium ion and iodide ion.

The dissociation of KI will be,

KI\rightarrow K^{+}+I^{-}

So, Van't Hoff factor = Number of solute particles = K^{+}+I^{-} = 1 + 1 = 2

(C) CaCl_2

It is an electrolyte that dissociates to give calcium ion and chloride ion.

The dissociation of CaCl_2 will be,

CaCl_2\rightarrow Ca^{2+}+2Cl^{-}

So, Van't Hoff factor = Number of solute particles = Ca^{2+}+2Cl^{-} = 1 + 2 = 3

(D) MgSO_4

It is an electrolyte that dissociates to give magnesium ion and sulfate ion.

The dissociation of MgSO_4 will be,

MgSO_4\rightarrow Mg^{2+}+SO_4^{2-}

So, Van't Hoff factor = Number of solute particles = Mg^{2+}+SO_4^{2-} = 1 + 1 = 2

(E) Non-electrolyte

The dissociation non-electrolyte is not possible. So, the Van't Hoff factor will always be, 1.

Hence, the highest van't Hoff factor of solute is, AlCl_3

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Natali [406]

Answer:

B.Rutherford's

Explanation:

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The answer is A hopefully this help you
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just go on Omegle

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