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Allisa [31]
4 years ago
11

Typically a Switch operates at layer 2 of the OSI model. However, small organizations, such as a SOHO, can purchase a switch tha

t also interprets Layer 3 data and works much like a router. What is this device called
Physics
1 answer:
Romashka-Z-Leto [24]4 years ago
6 0

Answer:

Layer 3 switch.

Explanation:

A layer 3 switch carrys out both the function of a switch and a router. It acts as a switch that links all the devices that are on the same subnet or virtual LAN at lightning speeds and has IP routing intelligence built into it to carry out the function of a router. It can support routing protocols, check incoming packets, and can also carry out routing decisions based on the source and the destination addresses.

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When light enters a pair of glasses, it ______________ when it hits the glass
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Describe how energy is transferred through a mechanical wave. Enter your answer in the space provided.
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3 years ago
"If the object has a speed of" -2.5 m/s at x = 0m, find its speed at x = 5.00 m and its speed at x = 15.0 m.
frez [133]

Answer:

Hello your question has some missing parts attached below is the missing part

A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below.

answer : speed at x = 5 m = 3.35 m/s

              speed at x = 15m  = 5.12 m/s

Explanation:

initial speed( x = 0 ) = 2.5 m/s

speed at x = 5.00 m = ?

speed at x = 15 m = ?

Determine speed at x = 5 m

First we will apply the expression for work-energy theorem

w = \frac{1}{2} m(v^2 - v_{0}^2 )  ----- ( 1 )

where : w = 7.50J, v_{0} = 2.5m/s , m = 3.0 kg ( in the expression of work )

input values into equation 1

7.50 = 1/2 (3 ) ( v^2 - 2.5^2 )

7.50 = 3/2 ( v^2 - 6.25 )

5 j/kg = v^2 - 6.25

∴ v = √11.25 = 3.35 m/s

Determine speed at X = 15

first we will determine the work done form x = 5 to x = 15

W = 7.5J + 15J + 7.5J = 30J,  v_{0} = 2.5m/s , m = 3.0 kg

w = \frac{1}{2} m(v^2 - v_{0}^2 ) --- ( 2 )

equation2 becomes

30J = 1/2 ( 3 ) ( v^2 - 6.25 )

30J = 3/2 ( V^2 - 6.25 )

20 J/kg = v^2 - 6.25

v = √26.25 = 5.12 m/s

5 0
3 years ago
Asha walks 15 m west, then 20 m north, then 15 m east. Calculate the distance
DochEvi [55]

Distance walked to the west= 15m

" " " " north= 20m

" " " " east = 15m

Total Distance= (15+ 20+ 15) m

= 50m

Asha covered 50m distance in total.

7 0
3 years ago
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