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3 years ago

Explain how force (F=ma), momentum (p=mv), energy, and gravity play a part in a launching sequence.

2 answers:

8 0

If the mass bigger and the acceleration faster, the force is bigger(F = ma). The rate of change of momentum of an object is directly proportional to the resultant force applied and is in the direction of the resultant force(p=mc) The gravity can affect the resultant force as weight when the object launch.

sorry if there's any grammar mistake

almond37 [142]3 years ago

5 0

Force is directly proportional to acceleration and inversely proportional to the mass. The acceleration vector of an object is in the same direction of the net force vector.

Momentum is mass times velocity. If you take the derivative of momentum with respect to time, you get the answer of (m*a) So therefore F = the derivative of momentum.

An object has potential energy depending on the situation it is in. This includes location mostly. If you launch an object on a cliff, it has a large amount of potential energy which is quickly converted into kinetic energy once it starts moving.

Gravity accelerates an object toward the center of mass. In a projectiles case, that would be earth. So once you shoot a projectile, it will accelerate towards the earth at -9.8 meters per second squared. Gravity itself gives the object potential energy

Idk if this helped at all. Hopefully it helped you understand the concepts and you can then research them yourself more in depth. My bad if I made any mistakes

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A CD has a mass of 17 g and a radius of 6.0 cm. When inserted into a player, the CD starts from rest and accelerates to an angul

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Answer:

τ =9.41 * 10⁻⁴ N*m

Explanation:

Kinematics of the CD

The CD rotates with constant angular acceleration and its angular acceleration is calculated as follows:

$\alpha = \frac{\omega_{f}- \omega_{i}}{t}$ Formula (1)

Where:

α : angular acceleration. (rad/s²)

ωf: final angular velocity (rad/s)

ωi : initial angular velocity (rad/s)

t = time interval (s)

Data

ωf= 20 rad/s

ωi =0

t = 0.65 s.

Calculating of the angular acceleration of the CD

We replace data in the formula (1)

$\alpha = \frac{20 -0}{0.65}$

α = 30.77 rad/s²

Newton's second law in rotation:

F = ma has the equivalent for rotation:

τ = I * α Formula (2)

where:

τ : It is the net torque applied to the body. (N*m)

I : it is the moment of inertia of the body with respect to the axis of rotation (kg*m²)

α : It is angular acceleration. (rad/s²)

Calculating of the moment of inertia of the CD

The moment of inertia of a disk with respect to an axis perpendicular to the plane and passing through its center is calculated by the following formula:

I = (1/2) M*R² Formula (3)

Data

M= 17 g = 17/1000 kg = 0.017 kg : CD mass

R= 6.0 cm= 6/100 m = 0.06 m : CD radius

We replace data in the formula (3) :

I = (1/2) ( 0.017 kg)*(0.06 m)² = 3.06 * 10⁻⁵ kg*m²

Calculating of the net torque acting on the CD

Data

α = 30.77 rad/s²

I = 3.06 * 10⁻⁵ kg*m²

We replace data in the formula (2) :

τ = I * α

τ =( 3.06 * 10⁻⁵ kg*m²) * (30.77 rad/s²)

τ =9.41 * 10⁻⁴ N*m

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