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victus00 [196]
3 years ago
10

Explain how force (F=ma), momentum (p=mv), energy, and gravity play a part in a launching sequence.

Physics
2 answers:
luda_lava [24]3 years ago
8 0

If the mass bigger and the acceleration faster, the force is bigger(F = ma). The rate of change of momentum of an object is directly proportional to the resultant force applied and is in the direction of the resultant force(p=mc) The gravity can affect the resultant force as weight when the object launch.

<em>sorry</em><em> </em><em>if</em><em> </em><em>there</em><em>'s</em><em> </em><em>any</em><em> </em><em>grammar</em><em> </em><em>mista</em><em>ke</em>

almond37 [142]3 years ago
5 0
Force is directly proportional to acceleration and inversely proportional to the mass. The acceleration vector of an object is in the same direction of the net force vector.

Momentum is mass times velocity. If you take the derivative of momentum with respect to time, you get the answer of (m*a) So therefore F = the derivative of momentum.

An object has potential energy depending on the situation it is in. This includes location mostly. If you launch an object on a cliff, it has a large amount of potential energy which is quickly converted into kinetic energy once it starts moving.

Gravity accelerates an object toward the center of mass. In a projectiles case, that would be earth. So once you shoot a projectile, it will accelerate towards the earth at -9.8 meters per second squared. Gravity itself gives the object potential energy

Idk if this helped at all. Hopefully it helped you understand the concepts and you can then research them yourself more in depth. My bad if I made any mistakes
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They give off a particle to become stable.
6 0
3 years ago
to measure the static friction coefficient between a block and a vertical wall, a spring is attached to the block, is pushed on
Stolb23 [73]

Answer:

μ = mg/kx

Explanation:

Since the bock does not slip, the frictional force equals the weight of the block. So, F = mg. Now, the frictional force, F = μN where μ = coefficient of static friction and N = Normal force.

Now, the normal force equals the spring force F' = kx where k = spring constant and x = compression of spring.

N = F' = kx

So, F = μN = μkx

μkx = mg

So, μ = mg/kx

8 0
3 years ago
A body travels 80 meters in 8 seconds <br> at a steady speed calculate it's average speed<br>​
iVinArrow [24]

Explanation:

avg spd = total distance/total time

=80/8=10m/s

7 0
4 years ago
When you go "down" the food chain by continuing to ask "what does it eat?" at what category of living things do you always end u
Klio2033 [76]

Answer:

Autotrophs

Explanation:

When you go down a food chain continuing to ask "what does it eat?" the last living thing that you will land upon is an autotroph.

Autotrophs are the primary producers as they (photoautotrophs) use the energy either from the sun to prepare  there food by the process of photosynthesis or, more rarely, obtain chemical energy through oxidation (chemoautotrophs) to make organic substances from inorganic ones.

Autotrophs get consumed by the primary consumers in the food chain.

7 0
3 years ago
Astronomers have observed a small, massive object at the center of our Milky Way Galaxy. A ring of material orbits this massive
Setler [38]

Answer:

The mass of the massive object at the center of the Milky Way galaxy is 3.44\times10^{37}\ Kg

Explanation:

Given that,

Diameter = 10 light year

Orbital speed = 180 km/s

Suppose determine the mass of the massive object at the center of the Milky Way galaxy.

Take the distance of one light year to be 9.461×10¹⁵ m. I was able to get this it is 4.26×10³⁷ kg.

We need to calculate the radius of the orbit

Using formula of radius

r=\dfrac{d}{2}

r=\dfrac{15\times9.461\times10^{15}}{2}

r=7.09\times10^{16}\ m

We need to calculate the mass of the massive object at the center of the Milky Way galaxy

Using formula of mass

M=\dfrac{v^2r}{G}

Put the value into the formula

M=\dfrac{(180\times10^3)^2\times7.09\times10^{16}}{6.67\times10^{-11}}

M=3.44\times10^{37}\ Kg

Hence, The mass of the massive object at the center of the Milky Way galaxy is 3.44\times10^{37}\ Kg

5 0
3 years ago
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