Answer
given,
radius of the circular orbit, r = 0.53 x 10⁻¹⁰ m
mass of electron, M = 9.11 x 10⁻³¹ Kg
charge of electron, q₁ = 1.6 x 10⁻¹⁹ C
q₂ = 1.6 x 10⁻¹⁹ C
we know, force between two charges


F = 8.20 x 10⁻⁸ N
b) using newton's second law
F = m a
m a = 8.20 x 10⁻⁸

a = 9 x 10²² m/s²
c) speed of the electron


v² = 4.77 x 10¹²
v = 2.18 x 10⁶ m/s
d) the period of the circular motion.



T = 1.53 x 10⁻¹⁶ s
Answer:
Pencil is to pen
Step by step explanation:
They are similar items, as they are both tools, but are different as to how they function.
Amman oak smoke skins kaons
Variables:
Source charge, Q = 3 micro C = 3 * 10^ - 6 C
E = electric field = 2.86 * 10 ^5 N/C
K = 8.99 * 10^9 N * m^2 / C
d = distance = ?
Formula:
E = K * Q / (d^2) => d^2 = K * Q / E
=> d^2 = 8.99 * 10^9 N * m^2 / C * 3 * 10^ -6 C / (2.86 * 10^ 5 N/C)
d^2 = 9.43 * 10 ^ -2 m^2
=> d = 3.07 * 10^-1 m
Answer: 0.307 m
Note: it is a long distance due to the Electric field is very low
Answer:
W = 907963.50 J = 907.96 J
Explanation:
Note: Refer to the figure attached
Now, from the figure we have similar triangles ΔAOB and ΔCOD
we have

or

Now, the work done to empty the tank can be given as:

or

or

or

or
![W = 6773.76\pi[\frac{5}{3}x^3-\frac{1}{4}x^4]^4_0](https://tex.z-dn.net/?f=W%20%3D%206773.76%5Cpi%5B%5Cfrac%7B5%7D%7B3%7Dx%5E3-%5Cfrac%7B1%7D%7B4%7Dx%5E4%5D%5E4_0%20)
or
![W = 6773.76\pi[\frac{128}{3}]](https://tex.z-dn.net/?f=W%20%3D%206773.76%5Cpi%5B%5Cfrac%7B128%7D%7B3%7D%5D%20)
or
W = 907963.50 J = 907.96 J