Answer:
Therefore,
The speed of the wave on the longer wire is 95 m/s.
Explanation:
Given:
For Short wire, speed is
Let length of Short and Longer wire be 
such that
To Find:
Speed on the longer wire
Solution:
The speed of a pulse or wave on a string under tension can be found with the equation,
Where,
= Tension on the wire
L = Length of Sting
m = mass of String
So here we have,
= same
Therefore,
......equation ( 1 )
And
.......equation ( 2 )
Dividing equation 1 by equation 2 and on Solving we get
Therefore,
Therefore,
The speed of the wave on the longer wire is 95 m/s.
Answer:
The distance covered is 40 m and the displacement is 31,6m.
Explanation:
The distance covered is the sum of the two distances (10+30). The displacement is equal to the distance of the hipotenusa of the triangle that the two distances (10 m to north and 30m to east) create. Using the Pythagoras theorem the displacent is equal to the Square root of (30^2 +10^2) .
The object is at rest.
This is due to the fact hwen two forces act upon each other on opposite sides, the movement of the object does not change due to the net force equaling 0.
Answer:
C) 8.0 N
Explanation:
F=m*a
The 78g box, since it has less weight, would accelerate faster. If you had a frictionless surface, and you conducted this experiment, both boxes, without any outside forces, would accelerate at the same rate forever. However, in this problem we must assume the surface is not frictionless. Friction is determined by weight; the more weight, the more friction. Since the 78g box has less weight, it has less friction, making it easier to push with less force.
