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Lena [83]
3 years ago
9

Does the work cause a change in kinetic energy or a potential energy?

Physics
1 answer:
Alla [95]3 years ago
3 0

Answer:

Work cause a change in kinetic energy

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PLZ help this should be super easy
Ugo [173]
The answer is number (3) if am wrong am sry
4 0
3 years ago
Read 2 more answers
⦁ Match the following terms:
ki77a [65]

Answer:

Mass number - ⦁ The number of protons and neutrons in the nucleus of an atom.

Isotopes - ⦁ Atoms with the same number of protons, but different number of neutrons.

Nitrogen - ⦁ The name of the element with atomic number 7.

Atomic number - ⦁ The number of protons in the nucleus of an atom.

4 0
2 years ago
A child pulls a sled up a snow covered hill. If the child does 504J of work on the sled while pulling the sled 23m up the hill t
zhenek [66]

Explanation:

ans is equal to 504j* 23 m* 10 ms

7 0
2 years ago
Which best symbolizes the hydrogen bonding between two water molecules?
Artemon [7]

The best symbolizes the hydrogen bonding between two water molecules is given in the diagram.

<h3 /><h3>What is hydrogen bonding?</h3>

A hydrogen bond is an attraction between an electronegative atom carrying a single pair of electrons—the hydrogen bond acceptor—and a hydrogen atom that is covalently bonded to a more electronegative "donor" atom or group.

One definition of a polar covalent bond is one in which one atom has a stronger alternation for electron negativity difference between two bonds, the more polar the link.

Polar molecules like H2O have a mild partial negative charge in one area and a partial positive charge in another.

to learn more about hydrogen bond go to -

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4 0
1 year ago
Pls help answer embed <br>​
Savatey [412]

Answer:

C = 1.01

Explanation:

Given that,

Mass, m = 75 kg

The terminal velocity of the mass, v_t=60\ m/s

Area of cross section, A=0.33\ m^2

We need to find the drag coefficient. At terminal velocity, the weight is balanced by the drag on the object. So,

Weight of the object = drag force

R = W

or

\dfrac{1}{2}\rho CAv_t^2=mg

Where

\rho is the density of air = 1.225 kg/m³

C is drag coefficient

So,

C=\dfrac{2mg}{\rho Av_t^2}\\\\C=\dfrac{2\times 75\times 9.8}{1.225\times 0.33\times (60)^2}\\\\C=1.01

So, the drag coefficient is 1.01.

5 0
3 years ago
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