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xeze [42]
3 years ago
11

Give the method of heat transfer and give it application in a thermoflask​

Physics
2 answers:
fenix001 [56]3 years ago
6 0

Answer:

Conduction in solids, Convention in of fluids, Radiation goes through anything it is allowed to pass through......

Explanation:

OlgaM077 [116]3 years ago
5 0

Answer:

conduction, convection and radiation

cork support prevents conduction

silvery double wall prevents radiation

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What is the term for a discrepancy between appearance and reality, or between what a character expects and what happens?
Verizon [17]

Answer:

I believe it is structural irony

3 0
3 years ago
NEED HELP WITH THIS!!!
ludmilkaskok [199]
If a bus starts a zero and then travels 10 miles north but then travels south 3.75 towards the starting point of zero, the displacement will be 10 - 3.75 = 7.5 miles
4 0
3 years ago
Please help it's for a test.
Andreas93 [3]

Answer:

Explanation:

KE=\frac{1}{2}mv^2 so filling in:

KE=\frac{1}{2}(1000)(30)^2 so to 2 sig figs (which is actually not accurate, but oh well...)

KE = 450000 J

If we want to find out how high it will have to travel up a hill so that its PE is the same as the KE at this speed, we set the value for KE = to PE:

450000 = (1000)(9.8)h so

h=\frac{450000}{(1000)(9.8)}=45.9m

7 0
3 years ago
4 points
zubka84 [21]

(a) 25lx

(b) 11.11lx

<u>Explanation:</u>

Illuminance is inversely proportional to the square of the distance.

So,

I = k\frac{1}{r^2}

where, k is a constant

So,

(a)

If I = 100lx and r₂ = 2r Then,

I_2 = k\frac{1}{(2r)^2}

Dividing both the equation we get

\frac{I_1}{I_2} = \frac{k}{r^2} X\frac{(2r)^2}{k} \\\\\frac{I_1}{I_2} = 4\\\\I_2 = \frac{I_1}{4}\\\\I_2 = \frac{100}{4}  = 25lx

When the distance is doubled then the illumination reduces by one- fourth and becomes 25lx

(b)

If I = 100lx and r₂ = 3r Then,

I_2 = k\frac{1}{(3r)^2}

Dividing equation 1 and 3 we get

\frac{I_1}{I_2} = \frac{k}{r^2} X\frac{(3r)^2}{k} \\\\\frac{I_1}{I_2} = 9\\\\I_2 = \frac{I_1}{9}\\\\I_2 = \frac{100}{9}  = 11.11lx

When the distance is tripled then the illumination reduces by one- ninth and becomes 11.11lx

3 0
3 years ago
Check the correctness of given equation<br> s = ut + (1/2)at^2
ruslelena [56]

Lets use Dimensional analysis.

\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2

<h3>LHS:-</h3>

\\ \sf\longmapsto s=\left[M^0LT^0\right]

<h3>RHS</h3>

\\ \sf\longmapsto ut+\dfrac{1}{2}at^2

\\ \sf\longmapsto \left[M^0LT^{-1}\right]\left[M^0L^0T^1\right]+\dfrac{1}{2}\left[M^0LT^{-2}\right]\left[M^0L^0T^1\right]^2

\\ \sf\longmapsto L+\dfrac{1}{2}\left[LT^{-2}\right]\left[T^2\right]

\\ \sf\longmapsto L+\dfrac{1}{2}L

\\ \sf\longmapsto \dfrac{2L}{2}

\\ \sf\longmapsto [L^1]

\\ \sf\longmapsto \left[M^0LT^0\right]

LHS=RHS

Hence verified

6 0
3 years ago
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