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2 years ago

Match the definition with the correct term: resistance to flow.

1 answer:

3 0

(1) friction is the force resisting the relative motion of solid surfaces , fluid layers and material elements sliding against each other.
(2) gravity is a science fiction .
(3) Resistance ::: is a property of a conductor by which the passage of current is opposed causing electric energy to be transformed into heat .
(4) viscosity is the quantity that describes a fluid.
(5)

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Amy has a mass of 30 kg, and she is riding a skateboard traveling 5 m/s. What is her momentum

soldi70 [24.7K]

We Know, P = m*v
Here, m = 30 Kg
v = 5 m/s

Substitute it into the expression,
P = 30*5 Kgm/s
P = 150 Kgm/s

So, your final answer is 150 Kg.m/s

Hope this helps!

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2 years ago

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What does WNBA stand for

Alexeev081 [22]

Answer:The Women's National Basketball Association,

Explanation:Branliest:)

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2 years ago

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if a student lifts their weight of 450 newtons up a set of stairs 5 meters high, how much work did they do?

irina1246 [14]

Answer:

2,250J

Explanation:

W = Fs = (450)(5) = 2,250

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1 year ago

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What is the Ultraviolet Catastrophe?

Sholpan [36]

The ultraviolet catastrophe was the prediction of late 19th century/early 20th century classical physics that an ideal black body (also blackbody) at thermal equilibrium will emit radiation in all frequency ranges, emitting more energy as the frequency increases.

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2 years ago

A stone is dropped into a river from a bridge 41.7 m above the water. Another stone is thrown vertically down 1.80 s after the f

hram777 [196]

Answer:

31.75 m/s

Explanation:

h = 41.7 m

Let the initial velocity of the second stone is u

Let the time taken to reach to the bottom by the first stone is t then the time taken by the second stone to reach the ground is t - 1.8.

For first stone:

Use second equation of motion

$h=ut+\frac{1}{2}gt^2$

Here, u = 0, g = 9.8 m/s^2 and t be the time and h = 41.7

So, 41.7= 0 + 0.5 x 9.8 x t^2

41.7 = 4.9 t^2

t = 2.92 s ..... (1)

For second stone:

Use second equation of motion

$h=ut+\frac{1}{2}gt^2$

Here, g = 9.8 m/s^2 and time taken is t - 1.8 = 2.92 - 1.8 = 1.12 s, h = 41.7 m and u be the initial velocity

$h=u\left ( t-1.8 \right )+4.9\left ( t-1.8 \right )^2$ .... (2)

By equation the equation (1) and (2), we get

$41.7=1.12 u +4.9 \times 1.12^{2}$

u = 31.75 m/s

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2 years ago