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2 years ago

What is the concentration created when 380.0g of Pb(NO3)2 is added to 330.0 mL of solution?

Chemistry

1 answer:

Juliette [100K]2 years ago

7 0

The concentration of lead nitrate is 3.48 M.

<u>Explanation:</u>

The molarity can be found by dividing moles of sucrose by its volume in litres. We can find the number of moles of sucrose by dividing the given mass by its molar mass. Now we can find the moles as,

Here mass of Pb(NO₃)₂ is 380 g

Molar mass of Pb(NO₃)₂ is 331.2 g/mol

Number of moles = $$\frac{given mass}{molar mass}$

= $$ \frac{380 g }{331.2 g/mol}$

= 1.15 moles

Volume in Litres = 330 ml = 0.33 L

Molarity = $$\frac{Moles}{Volume (L)}$

= 3.48 mol/L or 3.48 M

So the concentration of lead nitrate is 3.48 M.

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2 years ago

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