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Eddi Din [679]
3 years ago
13

a ball is thrown straight upward from point A, reaches a maximum height at point B, then falls back to point C, what is true abo

ut the balls velocity and acceleration the highest point B?
Physics
1 answer:
taurus [48]3 years ago
5 0

Answer:it has high amounts of potential energy.

Explanation:

When it reaches said peak gravity is pulling it down and it will evidently come down, which is energy.

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Hydrogen is a pure substance represented by the chemical symbol H. Which of the following best describes hydrogen?
Korvikt [17]
Hydrogen is an element made of only one kind of atom
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According to ancient greek thought, what is the difference between violent and natural motion
zzz [600]
Natural was thought to be straight up or straight down and violent was thought to be the result of a push or pull
7 0
3 years ago
The launching velocity of a missile is 20.0 m/s, and it is shot at 53º above the horizontal. What is the vertical component of t
Margaret [11]
The vertical component is given by the sin of the angle.  So this is 20*sin(53)=15.97m/s
8 0
3 years ago
A 149 turn 149 turn circular coil of radius 2.15 cm 2.15 cm is immersed in a uniform magnetic field that is perpendicular to the
adoni [48]

Answer:

Explanation:

number of turns, N = 149

radius, r = 2.15 cm

Area, A = πr² = 3.14 x 2.15 x 2.15 x 10^-4 = 1.45 x 10^-3 m^2

Change in magnetic field, ΔB = 95.5 - 50.5 = 45 mT = 45 x 10^-3 T

time, Δt = 0.165 second

induced emf

e = N x dФ/dt

where, dФ be the change in flux.

e = N x A x ΔB/Δt

e = 149 x 1.45 x 10^-3 x 45 x 10^-3 / 0.165

e = 0.058 V

4 0
3 years ago
Lora (of mass 43.6 kg) is an expert skier. She starts at 3.6 m/s at the top of the lynx run, which is 67 m above the bottom. Wha
Likurg_2 [28]

Explanation:

As per the law of conservation of energy, the final mechanical energy of Lora is equal to its initial mechanical energy. So, when Lora is at the bottom of ski run then her potential energy will change into kinetic energy.

Hence,   E_{initial} = \frac{mv_{i}^{2}}{2} + mgh


              E_{final} = \frac{mv_{f}^{2}}{2}

Now, final kinetic energy that will be at the bottom of the ski run is as follows.

Let,          E_{k} = E_{final}

            E_{intial} = E_{final}

          E_{k} = \frac{mv_{i}^{2}}{2} + mgh


                   = \frac{(43.6 \times (3.6)^{2}}{2} + (43.6 \times 9.81 \times 67)

                   = 282.53 + 28656.97

                  = 28939.502 J

Thus, we can conclude that her final kinetic energy at the bottom of the ski run is 28939.502 J.

3 0
3 years ago
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