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Grace [21]
3 years ago
15

According to ancient greek thought, what is the difference between violent and natural motion

Physics
1 answer:
zzz [600]3 years ago
7 0
Natural was thought to be straight up or straight down and violent was thought to be the result of a push or pull
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A man 6 feet tall walks at a rate of 6 feet per second away from a light that is 15 feet above the ground.
Tems11 [23]

Answer:(a)10 ft/s

(b)4 ft/s

Explanation:

Given

height of light =15 feet

height of man=6 feet

\frac{\mathrm{d} x}{\mathrm{d} t}=6 ft/s

From diagram

\frac{15}{y}=\frac{6}{y-x}

5(y-x)=2y

3y=5x

differentiate both sides

3\times \frac{\mathrm{d} y}{\mathrm{d} t}=5\times \frac{\mathrm{d} x}{\mathrm{d} t}

Tip of shadow is moving at the rate of

\frac{\mathrm{d} y}{\mathrm{d} t}=\frac{5}{3}\times 6=10 ft/s

(b)rate at which length of his shadow  is changing

Length of shadow is y-x

differentiating w.r.t time

\frac{\mathrm{d} (y-x)}{\mathrm{d} t}=\frac{\mathrm{d} y}{\mathrm{d} t}-\frac{\mathrm{d} x}{\mathrm{d} t}

\frac{\mathrm{d} (y-x)}{\mathrm{d} t}=10-6=4 ft/s

7 0
3 years ago
Different forces were applied to five balls, and each force was applied for the same amount of time. The data is in the table.
emmainna [20.7K]
C. It doubles I hope this helps and good luck
6 0
3 years ago
Read 2 more answers
Pls help i begg youuuuu
Anna [14]
Pitch is the sensation of certain frequencies to the ear. High frequency = high pitch, low frequency = low pitch. 

f = c(speed of the wave) /  <span>λ (wavelength)

1. 343m/s / 0.77955m = 439.99 Hz   
     This corresponds to pitch A 

2. 343m/s / 0.52028m = 659.26 Hz
</span>     This corresponds to pitch E 
<span>
3. 343m/s / 0.65552m = 523.349 Hz
    </span>This corresponds to pitch C

4. using f = c /  λ
  λ = c / f<span>
     = 343m/s / 587.33 = 0.583999 m = 0.584 m

</span>
3 0
3 years ago
Can someone help me w this ?
lukranit [14]

Answer:

i can't sorry

Explanation:

I didn't really pay attention in that class

7 0
2 years ago
A coin released at rest from the top of a tower hits the ground after falling 1.5 s. What is the speed of the coin as it hits th
Inessa05 [86]

initially coin is at rest and then it drop for total time t = 1.5 s

so here the speed of the coin at which it will hit the floor is to be find

v_f = v_i + at

here we know that

v_i = 0

a = 9.8 m/s^2

t = 1.5 s

now from above equation

v_f = 0 + 1.5 (9.8)

v_f = 14.7 m/s

so it will hit the floor with speed 14.7 m/s

3 0
3 years ago
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