Answer:
Electric field, E = 0.064 V/m
Explanation:
It is given that,
Resistivity of silver wire, 
Current density of the wire, 
We need to find the magnitude of the electric field inside the wire. The relationship between electric field and the current density is given by :


E = 0.0636 V/m
or
E = 0.064 V/m
So, the magnitude of electric field inside the wire is 0.064 V/m. Hence, this is the required solution.
I think the answer would be 1 watt but i'm not sure
The answer is Balance. hopei helped? ahahahaha
You have to add 1.7 and 2.2 together!
1.7+2.2=3.9μF
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