All categories

3 years ago

Which is an element? water carbon dioxide air hydrogen?

2 answers:

4 0

Water and carbon dioxide are compounds. Air is a mixture. The element that is listed is hydrogen.

Remember that you can also find elements on a periodic table.

Your answer is hydrogen.

soldi70 [24.7K]3 years ago

3 0

The answer is hydrogen, hoped that helps:)

You might be interested in

HELP ME PLEASE

lions [1.4K]

Answer:

Explanation:

Definitely not in the cell theory

3 0

3 years ago

Convert 2.345 centimeters cubed to inches cubed. 1inch = 2.54cm

GalinKa [24]

Answer:

0.92322835

Explanation:

0.92322835 rounded= 0.9 or 0.92

3 0

3 years ago

Read 2 more answers

Iron (III) oxide and hydrogen react to form iron and water, like this: Fe 03(s)+3H9)2Fe(s)+3HO) At a certain temperature, a chem

belka [17]

The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound Amount

Fe₂O₃ 3.95 g

H₂ 4.77 g

Fe 4.38 g

H₂O 2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

Answer: The value of equilibrium constant for given equation is $1.0\times 10^{-4}$

Explanation:

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

For hydrogen gas:

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M$

For water:

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

$\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M$

For the given chemical equation:

$Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)$

The expression of equilibrium constant for above equation follows:

$K_{eq}=\frac{[H_2O]^3}{[H_2]^3}$

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}$

Hence, the value of equilibrium constant for given equation is $1.0\times 10^{-4}$

6 0

3 years ago

1. The gradual wearing away or breaking down of rocks by abrasion is a type of

kiruha [24]

Differential weathering or erosion

5 0

3 years ago

What is the concentration of O2(g), in parts per million, in a solution that contains 0.008 gram of O2(g) dissolved in 1000. gra

romanna [79]

Answer : The concentration of $O_2$ (g) in parts per million is, 8 ppm

Explanation : Given,

Mass of oxygen gas (solute) = 0.008 g

Mass of water (solvent) = 1000 g

First we have to calculate the mass of solution.

Mass of solution = Mass of solute + Mass of solvent = 0.008 + 1000 = 1000.008 g

Now we have to calculate the concentration of $O_2$ (g) in parts per million.

ppm : It is defined as the mass of solute present in one million $(10^6)$ parts by mass of the solution.

$ppm=\frac{\text{Mass of solute}}{\text{Mass of solution}}\times 10^6$

Now put all the given values in this expression, we get

$ppm=\frac{0.008g}{1000.008g}\times 10^6=7.99=8ppm$

Therefore, the concentration of $O_2$ (g) in parts per million is, 8 ppm

8 0

2 years ago