AnswerIm telling your teacher "Ms.Byrd" your in 8th grade and go to berry middle?
Explanation:
Answer:
![\large \boxed{0.64 \, \%}](https://tex.z-dn.net/?f=%5Clarge%20%5Cboxed%7B0.64%20%5C%2C%20%5C%25%7D)
Explanation:
Assume you are using 1 L of water.
Then you are washing 4 L of salty oil.
1. Calculate the mass of the salty oil
Assume the oil has a density of 0.86 g/mL.
![\text{Mass of oil} = \text{4000 mL} \times \dfrac{\text{0.86 g}}{\text{1 mL}} = \text{3440 g}](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20oil%7D%20%3D%20%5Ctext%7B4000%20mL%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B0.86%20g%7D%7D%7B%5Ctext%7B1%20mL%7D%7D%20%3D%20%5Ctext%7B3440%20g%7D)
2. Calculate the mass of salt in the salty oil
![\text{Mass of salt} = \text{3440 g} \times \dfrac{\text{5 g salt}}{\text{100 g oil}} = \text{172 g salt}](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20salt%7D%20%3D%20%5Ctext%7B3440%20g%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B5%20g%20salt%7D%7D%7B%5Ctext%7B100%20g%20oil%7D%7D%20%3D%20%5Ctext%7B172%20g%20salt%7D)
3. Calculate the mass of salt in the spent water
![\text{Mass of salt} = \text{1000 g water} \times \dfrac{\text{15 g salt}}{\text{100 g water}} = \text{150 g salt}](https://tex.z-dn.net/?f=%5Ctext%7BMass%20of%20salt%7D%20%3D%20%5Ctext%7B1000%20g%20water%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B15%20g%20salt%7D%7D%7B%5Ctext%7B100%20g%20water%7D%7D%20%3D%20%5Ctext%7B150%20g%20salt%7D)
4. Mass of salt remaining in washed oil
Mass = 172 g - 150 g = 22 g
5. Concentration of salt in washed oil
![\text{Concentration} = \dfrac{\text{22 g}}{\text{3440 g}} \times 100 \, \% = \mathbf{0.64 \, \%}\\\\\text{The concentration of salt in the washed oil is $\large \boxed{\mathbf{0.64 \, \%}}$}](https://tex.z-dn.net/?f=%5Ctext%7BConcentration%7D%20%3D%20%5Cdfrac%7B%5Ctext%7B22%20g%7D%7D%7B%5Ctext%7B3440%20g%7D%7D%20%5Ctimes%20100%20%5C%2C%20%5C%25%20%3D%20%5Cmathbf%7B0.64%20%5C%2C%20%5C%25%7D%5C%5C%5C%5C%5Ctext%7BThe%20concentration%20of%20salt%20in%20the%20washed%20oil%20is%20%24%5Clarge%20%5Cboxed%7B%5Cmathbf%7B0.64%20%5C%2C%20%5C%25%7D%7D%24%7D)
Create more of their species
![\qquad \qquad\huge \underline{\boxed{\sf Answer}}](https://tex.z-dn.net/?f=%5Cqquad%20%5Cqquad%5Chuge%20%5Cunderline%7B%5Cboxed%7B%5Csf%20Answer%7D%7D)
Here's the balanced equation for given Double displacement reaction ~
![\sf Pb(NO_3)_2 +2 \: KI = PbI_2 +2 \: KNO_3](https://tex.z-dn.net/?f=%20%5Csf%20Pb%28NO_3%29_2%20%2B2%20%5C%3A%20%20KI%20%3D%20PbI_2%20%20%2B2%20%5C%3A%20%20KNO_3)
The products fored are : Lead Iodide ( PbI2 ) and Potassium Nitrate ( KNO3 )