Answer:
165.76 L
Step:
1 mole = 22.4 L
Then 7.4 mole= 22.4L * 7.4 mole / 1 mole = 165.76 L
Answer:
Explanation:
In this case, we have a <u>Friedel-Craft reaction</u> (see figure 1). Usually in this type of reaction, the benzene ring is <u>bonded directly to the carbon that has the halide atom</u>. But in this specific case, this is not happening.
To understand why we have to remember the reaction mechanism of this reaction. As first, step the Cl-C bond attacks the
and we form a new bond between the alkyl halide and the
, finally the C-Cl bond is broken and a <u>carbocation is formed</u>. In this case, we will have a primary carbocation, a very <u>unstable species</u>. Therefore we will have a <u>methyl shift</u> to obtain a tertiary carbocation.
This tertiary carbocation will react with and continues the reaction. (See figure 2)
I hope it helps!
Answer:
The plant cell has a cell wall, chloroplasts, plastids, and a central vacuole—structures not found in animal cells.
Explanation:
that is my answer
2. I believe it would be two but then again this is an incomplete answer so it is not two. It's probably going to be 3. Or 1. Because I took this test before a while back and I'm almost a 100% sure it's 1 or 3. Hope this helps slightly!
The concentrations : 0.15 M
pH=11.21
<h3>Further explanation</h3>
The ionization of ammonia in water :
NH₃+H₂O⇒NH₄OH
NH₃+H₂O⇒NH₄⁺ + OH⁻
The concentrations of all species present in the solution = 0.15 M
Kb=1.8 x 10⁻⁵
M=0.15
![\tt [OH^-]=\sqrt{Kb.M}\\\\(OH^-]=\sqrt{1.8\times 10^{-5}\times 0.15}\\\\(OH^-]=\sqrt{2.7\times 10^{-6}}=1.64\times 10^{-3}](https://tex.z-dn.net/?f=%5Ctt%20%5BOH%5E-%5D%3D%5Csqrt%7BKb.M%7D%5C%5C%5C%5C%28OH%5E-%5D%3D%5Csqrt%7B1.8%5Ctimes%2010%5E%7B-5%7D%5Ctimes%200.15%7D%5C%5C%5C%5C%28OH%5E-%5D%3D%5Csqrt%7B2.7%5Ctimes%2010%5E%7B-6%7D%7D%3D1.64%5Ctimes%2010%5E%7B-3%7D)
![\tt pOH=-log[OH^-]\\\\pOH=3-log~1.64=2.79\\\\pH=14-2.79=11.21](https://tex.z-dn.net/?f=%5Ctt%20pOH%3D-log%5BOH%5E-%5D%5C%5C%5C%5CpOH%3D3-log~1.64%3D2.79%5C%5C%5C%5CpH%3D14-2.79%3D11.21)