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vampirchik [111]
3 years ago
5

If the solvent front is 68 mm and the ring front of an unknown is 48mm from the original spot, what is the rf value?

Chemistry
1 answer:
Nat2105 [25]3 years ago
3 0

<u>Given:</u>

Distance of solvent front = 68 mm

Distance of unknown = 48 mm

<u>To determine:</u>

The rf value

<u>Explanation:</u>

The retention factor or the rf value is given by the ratio of distance traveled by the unknown to the distance traveled by the solvent front

RF = distance by unknown/distance by solvent

RF = 48/68 = 0.706

Ans: the RF value is 0.706

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1. How many molecules of S2 gas are in 756.2 L?
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Answer: There are 2.032 \times 10^{25} molecules S_{2} gas are in 756.2 L.

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It is known that 1 mole of any gas equals 22.4 L at STP. Hence, number of  moles present in 756.2 L are calculated as follows.

Mole = \frac{Volume}{22.4 L}\\= \frac{756.2 L}{22.4 L}\\= 33.76 mol

According to mole concept, 1 mole of every substance contains 6.022 \times 10^{23} molecules.

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