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AysviL [449]
2 years ago
8

5. Write the names of the following ions.

Chemistry
1 answer:
Talja [164]2 years ago
5 0
A.) Phosphate ion or Orthophosphate
d.) Hydroxide
D.) Ammonium
e.) Iron
C.) Nitrate
f.) Sulfur dioxide
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8. What is the molecular formula of a compound if 0.50 moles of it contains 0.50
11Alexandr11 [23.1K]

Answer:

ew

Explanation:

de

3 0
3 years ago
Give the oxidation number of the element indicated for each compound.
NARA [144]

Answer:

a. C: +3 ; b. N: +5 ; c. S:+6 ; d. C: +4; e. Mn: +7 ; f. Cr: +6.

Explanation:

Global charges in molecules is 0

You sum all the oxidation states to determine the oxidation state for the compound.

Na₂C₂O₄ → Sodium oxalate → Global charge: 0

Oxidation state for C: +3

HNO₃ → Nitric acid → Global charge: 0

Oxidation state for N: +5

H₂SO₄ → Sulfuric acid → Global charge: 0

Oxidation state for S: +6

HCO₃⁻  →  Bicarbonate → Global charge: -1, this is an anion

Oxidation state for C: +4

KMnO₄ → Potassium permanganate → Global charge: 0

Oxidation state for Mn: +7

Cr₂O₇⁻ → Anion dichromate → Global charge: -2

Oxidation state for Cr: +6

8 0
3 years ago
When 3.0 grams of H2 is reacted with excess C at constant pressure, the reaction forms CH4 and releases 53.3 kJ of heat. C(s) +
Murrr4er [49]

Answer:

THE ENTHALPY OF REACTION IN KJ/MOL OF CH4 IS 7.07 KJ/MOL.

Explanation:

Mass of H2 = 3 g

Molar mass of H2 = 2 g/mol

Heat released = 53.3 kJ

Equation of the reaction:

C(s) + 2H2(g) -------> CH4(g)

First:

Calculate the number of moles of H2 that was used:

Number of moles = mass / molar mass

Number of moles = 3g / 2g

Number of moles = 1.5 moles

So therefore, when 53.3 kJ of heat was released from the reaction, 1.5 moles of hydrogen was used.

From the equation of the reaction, one mole of carbon reacts with two moles of hydrogen to form one mole of methane.

For 3 g of hydrogen, 1.5 mole of hydrogen is involved.

It means:

1.5 moles of hydrogen reacts with 0.75 moles of carbon and produces 0.75 moles of methane. This is so because the reaction occurs in 1: 2: 1 in respect to carbon, hydrogen and methane respectively.

So we can say that the production of 0.75 mole of methane will evolve 53.3 kJ of heat.

0.75 mole of methane releases 53.3 kJ of heat.

1 mole of methane will release ( 53.3 kJ * 1 / 0.75 )

= 71.0666 kJ of heat

In conclusion, the enthalpy of the reaction in kJ/ mole of CH4 is 71.07 kJ/mol.

7 0
3 years ago
Iodine-131 has a half-life of 8 days. If the amount of iodine-131 in the orginial sample is 8 g, how much iodine-131 will remain
hram777 [196]

1/32

Explanation it stated with half on 8 days then that means you divide 24 and 8 so its 3 and you have to multiply ✖ ½

7 0
3 years ago
The number of particles in 1 mole of hydrogen gas is ________.
ivanzaharov [21]
Hidrogen gas is a diatomic gas, this is H2, which means that one molecule of gas has two atoms (every molecule of hydrogen gas consists in H2).

The particles in gases are the molecules, not atoms.

So, every molecule is a particle, and when you are told that you have 1 mole of hygrogen gas means that you have 1 mole of H2 molecules which is the same that 1 mole of particles.

Therefore, the answer is one mole.
3 0
3 years ago
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