Question

What is the mass in grams of 2.21 mole of Ca3(PO4)4?

Answer 1

Answer:

1105.29 grams

Explanation:

If you calculate the molar mass of Ca3(PO4)4 you'll get 500.13. Molar mass is the mass of one mole of a substance. Multiply 500.1194 by 2.21 because we have 2.21 moles to get 1105.264 grams.

The molar mass of Ca is 40.078 grams, and there are 3 of them. So 40.078 x 3 is 120.234 grams.

The molar mass of P is 30.974 and there are 4 P's, so 30.974 x 4 is 123.896 grams.

The molar mass of O is 16 grams and there are 6 of them. Again, 16 x 16 is 256 grams.

Add up 120.234 + 123.896 + 256 to get the molar mass of Ca3(PO4)4, 500.13.