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N76 [4]
3 years ago
8

What is the mass in grams of 2.21 mole of Ca3(PO4)4?

Chemistry
1 answer:
lesya [120]3 years ago
7 0

Answer:

1105.29 grams

Explanation:

If you calculate the molar mass of Ca3(PO4)4 you'll get 500.13. Molar mass is the mass of one mole of a substance. Multiply 500.1194 by 2.21 because we have 2.21 moles to get 1105.264 grams.

The molar mass of Ca is 40.078 grams, and there are 3 of them. So 40.078 x 3 is 120.234 grams.

The molar mass of P is 30.974 and there are 4 P's, so 30.974 x 4 is 123.896 grams.

The molar mass of O is 16 grams and there are 6 of them. Again, 16 x 16 is 256 grams.

Add up 120.234 + 123.896 + 256 to get the molar mass of Ca3(PO4)4, 500.13.

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<h3>Equation :</h3>

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Use formula,

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If you have a density of 100 kg/L, and a mass of 1000 units, tell me the following: First what are the mass units? Secondly, what is the volume?

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The solubility of nacl at 30°c is 36.3 g/100 g of water. what mass of nacl is contained in a saturated solution that contains 30
sleet_krkn [62]
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