Answer:
80cm3 of water, and 60cm3 carbon IV oxide is formed while 20cm3 of oxygen is left unreacted.
Explanation:
From Gay-Lussac's law, there are five volumes of oxygen, 1 volume if propane, 4 volumes of water and three volumes of CO2. Applying this shows the reacting volumes as we have in the image attached, hence the volumes left after reaction.
<u>Answer:</u> The for the given reaction is
<u>Explanation:</u>
For the given chemical reaction:
Half reactions for the given cell follows:
<u>Oxidation half reaction:</u> ( × 2)
<u>Reduction half reaction:</u>
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
To calculate the of the reaction, we use the equation:
Putting values in above equation, we get:
To calculate standard Gibbs free energy, we use the equation:
Where,
n = number of electrons transferred = 2
F = Faradays constant = 96500 C
= standard cell potential = 0.406 V
Putting values in above equation, we get:
Hence, the for the given reaction is