All categories

3 years ago

Will Mark Brainliest!

Chemistry

2 answers:

Margarita [4]3 years ago

8 0

Answer:

C₄H₉O₂

Explanation:

just count the amount of atoms present in the model.

tatyana61 [14]3 years ago

5 0

Answer:

there now u can give him/her brainliest!! :)

Explanation:

You might be interested in

Which statement describes a chemical property of oxygen

grin007 [14]

Oxygen can combine with a metal to produce a compound

8 0

3 years ago

Read 2 more answers

Show that the Newton has the units of mass times acceleration

Dimas [21]

F = ma = (kg)(m/s2) = kg ´ m/s2 N

hope this helps :D

7 0

3 years ago

Balance the following chemical equation, then answer the following question.

julsineya [31]

Molar mass:

O2 = 31.99 g/mol
C8H18 = 144.22 g/mol

<span>2 C8H18(g) + 25 O2(g) = 16 CO2(g) + 18 H2O(g)

2 x 144.22 g --------------- 25 x 31.99 g
10.0 g ----------------------?? ( mass of O2)

10.0 x 25 x 31.99 / 2 x 144.22 =

7997.5 / 288.44 => 27.72 g of O2

hope this helps!

</span>

3 0

3 years ago

Gallium has two naturally occurring isotopes: 69ga with a mass of 68.9256 amu and a natural abundance of 60.11% and 71ga. use th

Nataly [62]

There are two naturally occurring isotopes of gallium: mass of Ga-69 isotope is 68.9256 amu and its percentage abundance is 60.11%, let the mass of other isotope that is Ga-71 be X, the percentage abundance can be calculated as:

%Ga-71=100-60.11=39.89%

Atomic mass of an element is calculated by taking sum of atomic masses of its isotopes multiplied by their percentage abundance.

Thus, in this case:

Atomic mass= m(Ga-69)×%(Ga-69)+X×%(Ga-71)

From the periodic table, atomic mass of Ga is 69.723 amu.

Putting the values,

$69.723 amu=(68.9256 amu)(\frac{60.11}{100})+X(\frac{39.89}{100})$

Thus,

$69.723 amu=41.4312 amu+X(\frac{39.89}{100})$

Rearranging,

$X=\frac{69.723 amu-41.4312 amu}{0.3989}=70.9246 amu$

Therefore, mass of Ga-71 isotope is 70.9246 amu.

7 0

3 years ago

Read 2 more answers

What is the molarity if I take 10mL of 20 volumes Hydrogen Peroxide?

Kryger [21]

Answer:

1.635 M

Explanation:

Given:

10 mL of 20 volumes Hydrogen Peroxide

Here,

20 volumes of Hydrogen Peroxide means that on decomposition of 1 mL of H₂O₂ 20 mL of O₂ is obtained

also,

means 1 dm³ of H₂O₂ solution produces 20 dm³ oxygen

Now,

at 298K and 1 atm

20 dm³ oxygen = $\frac{\textup{20}}{\textup{24.47}}$ moles

= 0.817 moles

also,

2H₂O₂ → 2H₂O + O₂

thus,

1 dm³ of solution must contain 2 × moles of O₂ as moles of H₂O₂

thus,

Number of moles of H₂O₂ = 2 × 0.817

Number of moles of H₂O₂ = 1.635 moles

Hence,

For 20 volume hydrogen peroxide is 1.635 M

3 0

3 years ago