All categories

3 years ago

If 24 moles oxygen gas combined with 24 moles hydrogen gas, what would be the limiting reactant?

1 answer:

dsp733 years ago

6 0

Hydrogen, since in H2O there are two hydrogen atoms per one oxygen atom. So the hydrogen atoms would run out first so that there are 12 H2O molecules, where all the hydrogen is used and there are 12 oxygen atoms left over

You might be interested in

What are the branches of chemistry and their definition?

-BARSIC- [3]

The five main branches of chemistry are organic chemistry, inorganic chemistry, analytical chemistry, physical chemistry and biochemistry. Chemistry can be further divided into many sub-branches that may fall under more than one of the main branches.

4 0

3 years ago

Do all waves need a material to travel through? HELPPPP

Natasha2012 [34]

No.
Electromagnetic waves can travel without a medium.

hope this helps and have a great day :)

7 0

3 years ago

For the following pairs of ions, use the concept that a chemical compound must have a net charge of zero to predict the formula

Dafna11 [192]

$\\ \sf\longmapsto FeP$

$\\ \sf\longmapsto Fe_2S_3$

$\\ \sf\longmapsto FeCl_2$

$\\ \sf\longmapsto MgCl_2$

$\\ \sf\longmapsto MgO$

$\\ \sf\longmapsto Mg_3N_2$

$\\ \sf\longmapsto Na_3P$

$\\ \sf\longmapsto Na_2S$

$\\ \sf\longmapsto CoO$

$\\ \sf\longmapsto Co_2S_3$

$\\ \sf\longmapsto AlCl_3$

$\\ \sf\longmapsto CsBr$

$\\ \sf\longmapsto Ti_2O_4$

$\\ \sf\longmapsto Ag_2S$

4 0

2 years ago

A gas used to extinguish fires is composed of 75 % CO2 and 25 % N2. It is stored in a 5 m3 tank at 300 kPa and 25 °C. What is th

tatyana61 [14]

Answer : The partial pressure of the $CO_2$ in the tank in psia is, 32.6 psia.

Explanation :

As we are given 75 % $CO_2$ and 25 % $N_2$ in terms of volume.

First we have to calculate the moles of $CO_2$ and $N_2$ .

$\text{Moles of }CO_2=\frac{\text{Volume of }CO_2}{\text{Volume at STP}}=\frac{75}{22.4}=3.35mole$

$\text{Moles of }N_2=\frac{\text{Volume of }N_2}{\text{Volume at STP}}=\frac{25}{22.4}=1.12mole$

Now we have to calculate the mole fraction of $CO_2$ .

$\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CO_2+\text{Moles of }N_2}$

$\text{Mole fraction of }CO_2=\frac{3.35}{3.35+1.12}=0.75$

Now we have to calculate the partial pressure of the $CO_2$ gas.

$\text{Partial pressure of }CO_2=\text{Mole fraction of }CO_2\times \text{Total pressure of gas}$

$\text{Partial pressure of }CO_2=0.75mole\times 300Kpa=225Kpa=225Kpa\times \frac{0.145\text{ psia}}{1Kpa}=32.625\text{ psia}$

conversion used : (1 Kpa = 0.145 psia)

Therefore, the partial pressure of the $CO_2$ in the tank in psia is, 32.6 psia.

3 0

3 years ago

If a sample of gas is located 10.2 cm from the injection point and the chart speed is 0.5 cm/min, what is the retention time?

Archy [21]

Answer : The retention time is, 20 min

Explanation :

Retention time : It is defined as the amount of time a compound spends on the column after it has been injected.

Formula of retention time is:

$\text{Retention time}=\frac{\text{Distance from injection point to center of peaks}}{\text{Chart recorded speed}}$

Given:

Distance from injection point to center of peaks = 10 cm

Chart recorded speed = 0.5 cm/min

Now put all the given values in the above formula, we get:

$\text{Retention time}=\frac{10cm}{0.5cm/min}$

Retention time = 20 min

Thus, the retention time is, 20 min

3 0

3 years ago