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Papessa [141]
3 years ago
14

Sulfur reacts with oxygen and creates two compounds. Compound A contains 1.34 g of sulfur for every 0.86 g of oxygen. Compound B

contains 11.63 g of sulfur for every 10.49 g of oxygen. What is the mass ratio of oxygen rounded to the nearest whole number
Chemistry
1 answer:
spayn [35]3 years ago
3 0

Answer:

The mass ratio of oxygen rounded to the nearest whole no. 3 : 2

Explanation:

According to Law of Multiple proportion when two elements combine to make two or more different compounds, the mass ratio of the two element in the first compound, when divided by the mass ratio of the second compound , form a simple whole number ratio.

Compound A contains 1.34 g of sulfur for every 0.86 g of oxygen

        \frac{1.34}{0.86}= 1.5

Compound B contains 11.63 g of sulfur for every 10.49 g of oxygen

      \frac{11.643}{10.49}= 1.0

Ratio of oxygen in each compound

   always put the larger number over the smaller number.

\frac{CompoundA}{Compound B}=\frac{1.5}{1.0}=\frac{3}{2}

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Can someone check my chem questions?
alekssr [168]
All of them are correct! good!!
7 0
3 years ago
Convert the following into balanced equations:
enyata [817]

Pb(NO₃)₂ + 2KI → PbI₂ + 2KNO₃

​

We must first convert from a word equation to a symbol equation:to a symbol equation:

Lead (II) Nitrate + Potassium Iodide → Lead (II) Iodide + Potassium Nitrate

The lead (II) ion is represented as Pb²⁺ , whilst the nitrate ion is NO⁻₃

To balance the charges, we require two nitrate ions per lead (II) ion, and so lead (II) nitrate is Pb(NO₃)₂

The potassium ion is K ⁺  and the iodide ion is I ⁻

The two charges balance in 1:1 ratio, giving a formula of KNO₃

The symbol equation is as follows:

Pb(NO₃)₂ + KI   →PbI₂ + KNO ₃

The most obvious change we must make, when balancing this equation, is to increase the number of nitrate ions on the right hand side of the equation. We can to this by placing a coefficient of 2 before the potassium nitrate:

Pb(NO₃)₂  +KI  →PbI₂  +2KNO₃

In doing this we have upset the balance of potassium ions on each side of the equation.

Again, we can fix this: we must simply place another coefficient of 2, this time before the potassium iodide:

Pb(NO₃)₂  +2KI   →   PbI₂  +2KNO ₃

Concluding :

Checking over the equations once more, you will notice that we initially had 1 iodide ion on the right hand side, but 2 on the left. However, we already dealt with this in balancing out potassium ions. Now, our equation is balanced.

And that's it! One last thing to add is that you may have noticed the irregularity in iodide ions rather than nitrate ions. In this case, you would arrived at the same answer simply by working backwards.

Learn more about balanced equation :

brainly.com/question/26694427

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3 0
2 years ago
How is an average mass different from a weighted mass
romanna [79]

In an average mass, each entry has equal weight. In a weighted average, we multiply each entry by a number representing its relative importance.

Assume that your class consists of 15 girls and 5 boys. Each girl has a mass of 54 kg, and each boy has a mass of 62 kg.

<em>Average mass</em> = (girl + boy)/2 = (54 kg + 62 kg)/2 = <em>58 kg</em>

<em>Weighted average (Method 1) </em>

Use the <em>numbers of each</em> gender (15 girls + 5 boys) ,

Weighted average = (15×54 kg + 5×62 kg)/20 = (810 kg + 310 kg)/20

= 1120 kg/20 = <em>56 kg</em>.

If you put all the students on one giant balance, their total mass would be

1120 kg and the average mass of a student would be <em>56 kg. </em>

<em>Weighted average (Method 2) </em>

Use the <em>relative percentages</em> of each gender (75 % girls and 25 % boys).

Weighted average = 0.75×54 kg + 0.25×62 kg = 40.5 kg + 15.5 kg = <em>56 kg</em>

Each girl contributes 40.5 kg and each boy contributes 15.5 kg to the <em>weighted average</em> mass of a student.

6 0
3 years ago
A beaker has a mass of 77.275 calculate this mass in mg
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By definitions of the prefixes in the metric system, the prefix milli- (abbreviated as m as in mg) indicates 1/1000 or 1 x 10^-3 of a gram. In this case, if a beaker has a mass of 77.275 g (I am assuming this is grams since most other units would make it too heavy or too light), we would multiply this by 1000 to convert it to milligrams. So 77.275 g = 77,275 mg.
4 0
3 years ago
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