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Papessa [141]
3 years ago
14

Sulfur reacts with oxygen and creates two compounds. Compound A contains 1.34 g of sulfur for every 0.86 g of oxygen. Compound B

contains 11.63 g of sulfur for every 10.49 g of oxygen. What is the mass ratio of oxygen rounded to the nearest whole number
Chemistry
1 answer:
spayn [35]3 years ago
3 0

Answer:

The mass ratio of oxygen rounded to the nearest whole no. 3 : 2

Explanation:

According to Law of Multiple proportion when two elements combine to make two or more different compounds, the mass ratio of the two element in the first compound, when divided by the mass ratio of the second compound , form a simple whole number ratio.

Compound A contains 1.34 g of sulfur for every 0.86 g of oxygen

        \frac{1.34}{0.86}= 1.5

Compound B contains 11.63 g of sulfur for every 10.49 g of oxygen

      \frac{11.643}{10.49}= 1.0

Ratio of oxygen in each compound

   always put the larger number over the smaller number.

\frac{CompoundA}{Compound B}=\frac{1.5}{1.0}=\frac{3}{2}

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Use this condensed chemical structure
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Explanation:

Ethanamine is a colourless gas having a strong 'ammonia- like' odour. It contains the -NH2 group which makes it an amine. It contains one carbon-carbon bond, five carbon-hydrogen bonds and two nitrogen-hydrogen bonds.

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Which statement describes the bonds in iron sulfate, FeSO4?
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Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.

Elements form bonds to increase their stability. The main types of bonds are:

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Regarding the bonds in FesO₄:

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Regarding the bonds in FesO₄, Fe and S have an ionic bond, while S and O have covalent bonds.

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5 0
2 years ago
At a certain temperature the rate of this reaction is first order in HI with a rate constant of :0.0632s
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Answer : The time taken for the reaction is, 28 s.

Explanation :

Expression for rate law for first order kinetics is given by :

k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}

where,

k = rate constant  = 0.0632

t = time taken for the process  = ?

[A_o] = initial amount or concentration of the reactant  = 1.28 M

[A] = amount or concentration left time 't' = 1.28\times \frac{17}{100}=0.2176M

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0.0632=\frac{2.303}{t}\log\frac{1.28}{0.2176}

t=28s

Therefore, the time taken for the reaction is, 28 s.

8 0
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