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Papessa [141]
3 years ago
14

Sulfur reacts with oxygen and creates two compounds. Compound A contains 1.34 g of sulfur for every 0.86 g of oxygen. Compound B

contains 11.63 g of sulfur for every 10.49 g of oxygen. What is the mass ratio of oxygen rounded to the nearest whole number
Chemistry
1 answer:
spayn [35]3 years ago
3 0

Answer:

The mass ratio of oxygen rounded to the nearest whole no. 3 : 2

Explanation:

According to Law of Multiple proportion when two elements combine to make two or more different compounds, the mass ratio of the two element in the first compound, when divided by the mass ratio of the second compound , form a simple whole number ratio.

Compound A contains 1.34 g of sulfur for every 0.86 g of oxygen

        \frac{1.34}{0.86}= 1.5

Compound B contains 11.63 g of sulfur for every 10.49 g of oxygen

      \frac{11.643}{10.49}= 1.0

Ratio of oxygen in each compound

   always put the larger number over the smaller number.

\frac{CompoundA}{Compound B}=\frac{1.5}{1.0}=\frac{3}{2}

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olga55 [171]
  The mass in grams  of nitric  acid that is required  to react  with 454g C7H8 is 932.72  grams

     calculation
find the  moles  of C7H8  used
moles = mass/molar mass

= 454 g/92  = 4.935  moles

balanced reacting  equation

C7H8  +3 HNO3  = C7H5N3O6  +3 H20
by  use of mole ratio between  C7H8  to  HNo3  which is  1:3  the moles of  HNO3  =4.935  x3 = 14.805  moles

mass of HNo3  =  moles  x molar mass
= 14.805  x 63  = 932.72  grams

part B

the  mass of  C7H5N3o6 = 2045.5 grams

calculate the moles of C7H8
= 829 g/92  g/mol  = 9.011  moles

by use of mole  ratio  between C7H8 to C7H5N3O6  which is  1:1  the moles of  C7H5N3O6  is also  = 9.011  moles

mass of  C7H5N3O6  is therefore  =  moles x molar mass

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8 0
4 years ago
PLEASE HELP I got this wrong on an exam but got it wrong and i don’t know why!
lord [1]

Answer:

D.5,55cm+/-0,005cm

Explanation:

so this is the answer

5 0
3 years ago
Can you pls tell me the net ironic equation of H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq)+SO²⁻₄(aq) + H₂O(l)
almond37 [142]

Answer:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

Explanation:

H₂²⁺(aq) + O₂²⁻(aq) + Mg²⁺(aq) + SO₃²⁻(aq) → Mg²⁺(aq) + SO²⁻₄(aq) + H₂O(l)

A careful observation of the equation above, shows that the equation is already balanced.

To obtain the net ionic equation, we simply cancel Mg²⁺ from both side of the equation as shown below:

H₂²⁺(aq) + O₂²⁻(aq) + SO₃²⁻(aq) → SO²⁻₄(aq) + H₂O(l)

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The concept used here is the Le Chatelier's principle. When a disturbance is introduced to the system, it favors the direction of reaction that minimizes the disturbance to regain equilibrium.

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Anna [14]

Answer:

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As is evident from the Stock number, mercury has an oxidation state of +1. This makes sense, as chlorine usually has an oxidation state of -1.

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