Answer:
The equilibrium concentration of NO is 0.001335 M
Explanation:
Step 1: Data given
The equilibrium constant Kc is 0.0025 at 2127 °C
An equilibrium mixture contains 0.023M N2 and 0.031 M O2,
Step 2: The balanced equation
N2(g) + O2(g) ↔ 2NO(g)
Step 3: Concentration at the equilibrium
[N2] = 0.023 M
[O2] = 0.031 M
Kc = 0.0025 = [NO]² / [N2][O2]
Kc = 0.0025 = [NO]² / (0.023)(0.031)
[NO] = 0.001335 M
The equilibrium concentration of NO is 0.001335 M
Science, Economics, Statistics, Finance, and many other areas of life where we are measuring things to a certain level of accuracy.
Answer:
your carbon footprint is how often you use a car of vehical you can decreese it by riding a bike or walking.
Explanation:
The molar mass of a, b and c at STP is calculated as below
At STP T is always= 273 Kelvin and ,P= 1.0 atm
by use of ideal gas equation that is PV =nRT
n(number of moles) = mass/molar mass therefore replace n in the ideal gas equation
that is Pv = (mass/molar mass)RT
multiply both side by molar mass and then divide by Pv to make molar mass the subject of the formula
that is molar mass = (mass x RT)/ PV
density is always = mass/volume
therefore by replacing mass/volume in the equation by density the equation
molar mass=( density xRT)/P where R = 0.082 L.atm/mol.K
the molar mass for a
= (1.25 g/l x0.082 L.atm/mol.k x273k)/1.0atm = 28g/mol
the molar mass of b
=(2.86g/l x0.082L.atm/mol.k x273 k) /1.0 atm = 64 g/mol
the molar mass of c
=0.714g/l x0.082 L.atm/mol.K x273 K) 1.0atm= 16 g/mol
therefore the
gas a is nitrogen N2 since 14 x2= 28 g/mol
gas b =SO2 since 32 +(16x2)= 64g/mol
gas c = methaneCH4 since 12+(1x4) = 16 g/mol
Answer:
See below.
Explanation:
1. The water here is the solvent, and the 'sugar and fruit specific chemicals' are considered the solute. That is as the solute is the component dissolved in the solvent.
2. The collision theory states that the greater the collisions, the greater the rate of reaction. When powdered sugar is placed in the water (solvent) it occupies more surface area, resulting in more collisions that speed up the rate of reaction, compared to a cube of sugar - that occupies less surface area. Therefore, the powdered sugar dissolved faster.
3. Molarity describes the number of moles of a substance per unit of volume. The standard unit of volume is liter, giving you the standard units (mol/l). Molality describes the number of moles per unit of mass, typically kilograms (mol/kg).
The concentration of a solution can be given in moles of solute dissolved per kilogram of solvent for molality, and moles of solute dissolved in liters of solvent for molarity. Molality is generally used for concentration.
