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Norma-Jean [14]
3 years ago
14

Find the area (7cm, 20cm, 11 cm, 14 cm

Mathematics
2 answers:
Likurg_2 [28]3 years ago
8 0

ok ... so the way i solved this is by finding the correct side measurements ... so in this there are 2 rectangles ... so lets find the area of both rectangles individually and then add it together ... so the rectangle on the top will be <em><u>a</u></em><em> </em>and the down one will be <u><em>b </em></u>

rectangle a :

as we know ... a <u>rectangle has opposite sides equal . </u> the side on the right is 20 ... subtract it from 11 ... if we do that we get 9 ... which is the length of rectangle a and as the top is 7 bottom will be 7 too

now we know the sides of rectangle <u>a </u>which is 7 and 9

and area of rectangle : l × b , ∴ 7×9= 63

now b ... sides of rectangle b are 14 and 11

so 14×11= 154

now add it ... <u>154 + 63 = 217 </u>

∴ = 217 sq.




LenKa [72]3 years ago
3 0
A = 7*9 +11*14
=63 + 154
=217 cm^2
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Since we are only interested in comparing the two at time t = 5 seconds, we plug in 5 everywhere we see the variable t and then compare x and y

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The ratio of y to x can be expressed as: y/x, so we can say the ratio is equal to 75/100 or 0.75

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Step-by-step explanation:

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Answer:

Null hypothesis:p \leq 0.69  

Alternative hypothesis:p > 0.69  

Step-by-step explanation:

1) Data given and notation

n=1500 represent the random sample taken

X represent the number of graduates that had student loan debt in 2014

\hat p=0.71 estimated proportion of adults that said that it is morally wrong to not report all income on tax returns

p_o=0.69 is the value that we want to test

\alpha represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that if there was a significant increase in the proportion of student loan debt for public and nonprofit colleges in 2014 respect to the value of 2013.:  

Null hypothesis:p \leq 0.69  

Alternative hypothesis:p > 0.69  

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.71 -0.69}{\sqrt{\frac{0.69(1-0.69)}{1500}}}=1.675  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level assumed is \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a right tailed test the p value would be:  

p_v =P(Z>1.675)=0.047  

If we compare the p value obtained and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of adults that said that it is morally wrong to not report all income on tax returns  is not significantly higher than 0.69.  

5 0
3 years ago
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NemiM [27]

Answer:

18:12 (accurate)

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Step-by-step explanation:

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The ratio you are trying to find is won to lost, or won:lost. Plug in the corresponding numbers to the corresponding terms:

won:lost ⇒ 18:12

18:12 is the ratio.

If the teacher asks you to simplify, factor both sides. Divide 6 from both sides:

(18)/6 : (12)/6

3:2

3:2 is your simplified ratio.

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A

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-2y-10

-2y-10

7 0
3 years ago
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