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3 years ago

jay beats terry at table tennis 3 out of 5 games. what is the experimental probability that terry will win their next game

Mathematics

1 answer:

lozanna [386]3 years ago

6 0

Answer:

The experimental probability that terry will win their next game is $\frac{2}{5}$

Step-by-step explanation:

While theoretical probability is the ratio of the number of favourable outcomes to the total number of outcomes, the experimental probability is the ratio of number of times the event is occurring to the total number of trials of the experiment.

Out of 5 games jay wins 3

Now the experimental probability that terry will win their next game

= 1 - Probability of Jay winning the game----------------------(1)

Probability of Jay winning the game = $\frac{\text{number of occurrences of the event}}{\text{total number of trials made}}$

=> $\frac{3}{5}$ ----------------------------------------------------(2)

Substituting (2) in (1)

=> 1 - $\frac{3}{5}$

=> $\frac{5-3}{5}$

=> $\frac{2}{5}$

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Find the distance between points M and N M= (3,-2) N= (5,-6)

Olin [163]

Answer:

$MN = \sqrt{(5-3)^{2}+(-6-(-2))^{2} } = \sqrt{2^{2}+(-4)^{2} } = \sqrt{20} = 2\sqrt{5}$

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3 years ago

Read 2 more answers

1. Identify each situation in which a quantity grows or decays by a constant percent rate per unit interval. A. The number of ca

zvonat [6]

Answer:

Step-by-step explanation:

1) For each situation to grow or decay by a constant percent rate, it must be exponential. Therefore, the correct examples are

A. The number of cars sold doubles every year. It is a 200% growth every year.

D. Each time you start a car engine the remaining engine life decreases by 0.0075%. A case of decay

E. The number of people creating cat videos increases by 15% percent every year.

F. Computer technology increases by a factor of 3 every five years.

2) this is a case of exponential decay. The expression for exponential decay is

y = b(1 - r)^t

y = final value

b = initial value

r = decay rate

t = time

Given that

r = 10% = 10/100 = 0.1

b = 50 kilograms

y = W kilograms

The relationship is

W = 50(1 - 0.1)^t

W = 50(0.9)^t

3 0

3 years ago

What is the value of s and the length of side BC if ABCD is a rhombus?

Natali5045456 [20]

Step 1

Find the value of s

we know that

In a Rhombus all sides are congruent

$AB=BC=CD=DA$

$AB=9s+29\\CD=10s-16$

equate AB and CD

$9s+29=10s-16\\$

Combine like term

$10s-9s=29+16\\$

$s=45\ units$

The answer Part a) is

the value of s is $45\ units$

Step 2

Find the value of side AB

$AB=9s+29$

substitute the value of s

$AB=9*45+29=434\ units$

Remember that the sides are congruent

$AB=BC=CD=DA$

therefore

the answer Part b) is

The length of the side BC is $434\ units$

4 0

3 years ago

Read 2 more answers

Conduct the appropriate hypothesis test and compute the test statistic. A company that produces fishing line undergoes random te

andre [41]

Answer:

Option D) Yes, because the test statistic is -2.01

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 30 pound

Sample mean, $\bar{x}$ = 29.1 pounds

Sample size, n = 20

Alpha, α = 0.05

Sample standard deviation, s = 2 pounds

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 30\text{ pounds}\\H_A: \mu < 30\text{ pounds}$

We use one-tailed(left) t test to perform this hypothesis.

Formula:

$t_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }$

Putting all the values, we have

$t_{stat} = \displaystyle\frac{29.1 - 30}{\frac{2}{\sqrt{20}} } = -2.012$

Now,

$t_{critical} \text{ at 0.05 level of significance, 19 degree of freedom } = -1.729$

Since,

$t_{stat} < t_{critical}$

We fail to accept the null hypothesis and reject it. We accept the alternate hypothesis. Thus, there were enough evidence to conclude that the fishing line breaks with an average force of less than 30 pounds.

Option D) Yes, because the test statistic is -2.01

5 0

3 years ago

Help i dont understand Pls help :(

olya-2409 [2.1K]

Answer:

x = 1?

Step-by-step explanation:

I think functions are basically just variables but extra so they both act the same. I'm not 100% sure but I Think

if f(x) = -5x + 1 when f(x) = 6,

replace f(x) with 6 so,

6 = 5x + 1

1 - 6 = 5x + 1 - 1

(subtract one on both sides to isolate the variable)

5 = 5x

5/5 = 5x/5

(to Actually isolate the variable lol

1 = x or x = 1

I believe is the answer? please comment if I'm wrong

*I WAS TOLD MY THOUGHT PROCESS IS WRONG ANYONE WHO SEES THIS PLEASE DISREGARD

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3 years ago