Answer:
Hey there!
Gold would have a greater mass, because density is mass/volume, and if the density is greater, so is the mass.
Let me know if this helps :)
<span>These are the rules of the quantum numbers that you have to use to dilucidate the validity of a set of quantum numbers:
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<span>1) Main quantum number, n: 1, 2, 3, 4, 5, 6, 7
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2) Second quantum number, ℓ: 0, 1, 2, ... n-1
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<span>3) Third quantum number (magnetic quantum number), mℓ: -l,...0,,,,+l
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<span>4) Fourth quantum number (spin): ms: +1/2 or -1/2
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Answers:
<span>i) 3,2,0,1/2: valid, because 0<= l < n; - l <= ml <= +l; and ms = +1/2 or -1/2
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</span><span>ii) 2,2,-1, 1/2 invalid because l = n (violates second rule)</span><span /><span>
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</span><span>iii) 4,3,-4,1/2 invalid because ml is less than - l (violates third rule)</span><span /><span>
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</span><span>iv) 1,0,0,1/2 valid: meet the four rules</span><span /><span>
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</span><span>v) 2,2,1,-1/2 invalid because l = n (violate the second rule)</span><span /><span>
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</span><span>vi) 3,2,1,1 invalid because ms can be only +1/2 or -1/2 (fourth rule)
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<span /><span /><span>vii) 0,1,1,-1/2 invalid because l > n (violates rule 2)
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<span /><span /><span>viii) 3,3,1,1/2 invalid because l = n (violate rule 2)
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<span /><span /><span>ix) 2,-2,-2,-1/2 invalid because l is negative (violates rule 2)
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x)<span> 3,2,2,1/2 valid: meet the four rules</span>
xi)<span> 4,2,1,1/2 valid: meet the four rules</span>
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</span><span>xii) 2,1,-1,-1/2 valid meet the four rules</span>
Answer:
1. 0.01000 moles of NaOH
2. 0.002680 moles of H₂C₂O₄
3. 0.005360 moles of NaOH
4. 0.004640 moles of NaOH
5. 0.004640 moles of ammonium salt
6. 123.5 g/mol
Explanation:
Ammonium ion (NH₄⁺) reacts with NaOH, thus:
NH₄⁺ + NaOH → NH₃ + H₂O + Na⁺ <em>(1)</em>
1. 50.00mL of 0.2000M NaOH contains:
0.05000L × (0.2000 mol / 1L) = <em>0.01000 moles of NaOH</em>
2. Oxalic acid (H₂C₂O₄) reacts with NaOH, moles of oxalic acid used during titration are:
0.02680L × (0.1000 mol / 1L) = <em>0.002680 moles of H₂C₂O₄</em>
3. The reaction of oxalic acid with NaOH is:
H₂C₂O₄ + 2NaOH → Na₂C₂O₄ + H₂O <em>(2)</em>
That means one mole of acid reacts with 2 moles of NaOH. Thus, moles of NaOH that remains after reaction with ammonium salt are:
0.002680 moles of H₂C₂O₄ × (2 mol NaOH / 1 mol H₂C₂O₄) = <em>0.005360 moles of NaOH</em>
4. Thus, moles of NaOH that reacted with ammonium salt are:
0.01000 moles of NaOH - 0.005360 moles of NaOH =<em> 0.004640 moles of NaOH</em>
5. Based in reaction (1), moles of NaOH ≡ moles of NH₄⁺. That means moles of ammonium salt in 0.573g of sample are <em>0.004640 moles of ammonium salt</em>
6. As moles of ammonium ion are the same than ammonium salt. Molar mass of the ammonium salt is:
0.573g / 0.004640 moles = <em>123.5 g/mol</em>