Answer:
112 molecules are formed from the reaction
Explanation:
Let's make the reaction:
S₈ + 8O₂ → 8SO₂
1 mol of S₈ reacts with 8 moles of O₂ to produce 8 moles of sulfur dioxide
Let's determine the moles ( amount of molecules / NA)
14 / 6.02x10²³ = 2.32x10⁻²³ mol of S
184 / 6.02x10²³ = 3.05x10⁻²² mol of O₂
As ratio is 1:8, the limiting reactant would be the sulfur. It's obviouly I do not have enough the amount of molecules.
8 mol of O₂ need 1 mol of S₈
3.05x10⁻²² mol of O₂ would need (3.05x10⁻²² / 8) = 3.81ₓ10²¹
Now, that we get the limiting, we can work with the reaction
1 mol of S₈ produce 8 mol of dioxide
Then, 2.32x10⁻²³ mol of S will produce (2.32x10⁻²³ . 8) = 1.85x10⁻²² moles of SO₂
Let's convert the moles in, amount of molecules (mol . NA)
1.85x10⁻²² mol . 6.02x10²³ = 112 molecules
