Answer:
145°
Step-by-step explanation:
There are a couple of ways you can get there:
1. ∠ACB is a right angle, 90°. Hence, ∠BAC is the complement of ∠ABC, so is ...
... ∠BAC = 90° -∠ABC = 90° -55° = 35°
Then, ∠BAC and ∠BAD are a linear pair, so total 180°. That makes ∠BAD the supplement of ∠BAC, so ...
... ∠BAD = 180° -35° = 145°
2. ∠BAD is the exterior angle at A for the triangle ABC. It will have a measure that is the sum of the opposite interior angles: given ∠ABC = 55° and right angle ACB = 90°.
... ∠BAD = 55° +90° = 145°
<h2>HI MATE YOUR ANSWER SHOULD BE 10/3</h2>
Answer:
(3, 2)
Step-by-step explanation:
Answer:

Step-by-step explanation:
Use distributive property: 
What is -x * x^2? Answer: -x^3
What is 3 * x^2? Answer: +3x^2
What is -x * -4x? Answer: +4x^2
What is 3* -4x? Answer: -12x
What is -x * -6? Answer: +6x
What is 3 * -6? Answer: -18

Combine like terms, and your answer would be....

Hope this helps :)
Have a great day!
Answer:
Congurent triangles are those which map onto them selves perfectly. This means they share the same angle measurements and side lengths. Therefor we can figure out the side lengths by using the information in both triangles.
AD=5x+11
in the congurent triangle, the corresponding side equals:
CM=7x-3
CM and AD are congurent triangles meaning their sidelengths equal the same. Therefore...
5x+11=7x-3
Now we just solve to find the length of AD and CM (equal lengths)
5x+11=7x-3
11=2x-3
14=2x
7=x
x=7
If x=7 then we can plug it in for AD to find the side length.
5(7)+11=46
Notice that CM equals the same 7(7)-3=46
This is because... they are congruent triangles.
These rules also apply for all angle measurements of congruent triangles:
The m<v is equal to the meaasure of E (corresponding angles in congrurent triangles are equal)
We already astablished what x was (x=7) meaning if we find the measure of E then we have the measure of V sicne they are corresponding angles in a congrurent triangle.
(6x7+1)=43°
therefore the m<v is equal to 43°
46 and 43° is your answer
Step-by-step explanation: