Can you help me in seeing if its right

Mathematics

1 answer:

Scorpion4ik [409]3 years ago

8 0

Answer: The answer to that would be 4/5= 32/40.

Step-by-step explanation: It is 4/5 =32/40 because if you were to divide the 40 by the 5 you would get 8. Since you got 8 when dividing 40 by 5 you would multiply 8x4. You would do this because whatever you do to the denominator you would do to the numerator. So you would multiply 4/5 x 8/8 and get 32/40. PLEASE MARK BRAINLIEST!!!!

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If c < d and x > 1, which of the following must be true?

Reika [66]

Answer:

logc(x) > logd(x)

Step-by-step explanation:

4 0

4 years ago

Use a form of the distributive property to rewrite the given algebraic expression without parentheses. 2(3x-3)

guajiro [1.7K]

Answer:

6x-6

Step-by-step explanation:

The Distributive property says that a(b+c) = ab+ac

In my example you distribute the value on the outside to the things on the inside

In your problem you have a two on the outside that needs to be distributed to a 3x and a -3

1) 2 multiplied by 3x equals 6x giving you the first part of your answer!

2) 2 multiplied by -3 equals -6 giving you the second part of your answer!

Don't forget that there is a - sign between the 3x and 3, don't drop it!

Put the two values together to get 6x-6

Let me know if you have any further questions :)

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4 years ago

A bacteria culture initially contains 100 cells and grows at a rate proportional to its size. After an hour the population has i

bija089 [108]

Answer: $\bold{a)\ P(t)=P_o\cdot e^{t\cdot ln(2.7)}}$

b) 5314

c) ln 2.7

d) 4.6 hrs

<u>Step-by-step explanation:</u>

$P(t) = P_o\cdot e^{kt}\\\\\bullet \text{P(t) is the number of bacteria after t hours} \\\bullet P_o\text{ is the initial number of bacteria}\\\bullet \text{k is the rate of growth}\\\bullet \text{t is the time (in hours)}\\\\\\270=100\cdot e^{k(1)}\\2.7=e^k\\ln\ 2.7=\ln e^k\\\boxed{ln\ 2.7=k}\\\\\text{So the equation to find the number of bacteria is: }\boxed{P(t)=P_o\cdot e^{t\cdot ln(2.7)}}\\\\\\P(4)=100\cdot e^{4\cdot ln(2.7)}\\.\qquad =\boxed{5314}$

$10,000=100\cdot e^{t\cdot ln(2.7)}\\100=e^{t\cdot ln(2.7)}\\ln\ 100=ln\ e^{t\cdot ln(2.7)}\\ln\ 100=t\cdot ln(2.7)\\\dfrac{ln\ 100}{ln\ 2.7}=t\\\\\boxed{4.6=t}$